Answer:
x = 4.4
Step-by-step explanation:
I'm going to assume you want to solve for x so here we go.
You need to work backwards for this equation, and whatever you do to the LHS, you do to the RHS.
First, you need to remove the minus 3, which means that on both sides, you add 3. Adding three on the LHS makes the -3 disappear, and adding 3 on the RHS makes the 19 go to a 22.
Your equation is now 5x=22.
Since 5x means 5 × x, to get rid of it, you need to divide 5x by 5. Doing it to the LHS will make the five disappear, and doing it to the RHS will make it go to 22 ÷ 5 which equals 4.4
Therefore, x = 4.4
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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You've got 3 values there.
Get the sum of 65, 30 and 25 and divide their sum by the number of values that exist, which in this case is 3.
Answer:
40
Answer:
3 (m^2 - 16)
Step-by-step explanation:
factoring means taking out a common multiple of all the terms in the expression
in this case, if you multiply 3 and m^2, 3 and -16, you would get 3m^2-48
so you take the three and put it outside of the parenthesis that contains the factored terms
this leaves you with 3 (m^2 - 16)
Not sure what the question is but 3x + 7 is the algebraic expression that would represent this statement.
