Answer:
A = [m/s]
B = [m/s²]
Explanation:
Assuming that V has SI units of m/s, then A and BT must also have units of m/s.
A = [m/s]
BT = [m/s]
Since T has SI units of s:
B [s] = [m/s]
B = [m/s²]
This is modelling.
Option D.
From the model, the conditions of the now are put into the model in order to predict the weather for a future date.
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Answer: The frequency heard is 562.7 Hz.
Explanation: <u>Doppler</u> <u>Effect</u> happens when there is shift in frequency during a realtive motion between a source and the observer of that source.
It can be calculated as:
where:
c is the speed of light (c = 332m/s)
all the subscripted s is related to the Source (frequency, velocity);
all the subscripted o is related to the Observer (frequency, velocity);
As the source is moving towards the observer and the observer is moving towards the source, the velocities of each are opposite related to direction.
So, the frequency perceived by the observer:
= 562.7 Hz
At this condition, the observer hears the train's horn in a perceived frequency of 562.7 Hz
Answer:
The amount of energy carried by a wave is related to the amplitude of the wave
Explanation:
A high energy wave is characterized by a high amplitude; a low energy wave is characterized by a low amplitude. The energy imparted to a pulse will only affect the amplitude of that pulse.
Hope this helped!!!
Answer:
(A) 1.01 s
(B)
Explanation:
horizontal distance (L) = 3 m
vertical height (h) = 1.25 m
acceleration due to gravity (g) = 9.8 m/s^{2}
(A) hang time refers to how long the person remains in the air, and is the summation of the time it took attain maximum height and the time it takes to get back to the ground.
- it is going to take the same amount of time to attain maximum height and to return to the ground.
- from s = ut + 0.5g we can get the time taken to attain maximum height.
where s = vertical distance = 1.25 m
u = initial velocity = 0 (since body starts from rest)
g = acceleration due to gravity = 9.8 m/s^{2}
t == time taken to get to maximum height
the equation now becomes s = 0.5g
1.25 = 0.5 x 9.8 x
= 1.25/(0.5x9.8)
t =
t = 0.505 s
- now that we have the time taken to attain maximum height which is also equal to the time it takes to get back to the ground.
total time = time taken to attain maximum height + time it takes to get back to the ground.
total time = 0.505 + 0.505 = 1.01 s
(B) when horizontal distance = 6 m , the hang time would remain the same, because the horizontal component does not affect the vertical component . Also we can see that from the equation used in part A above the horizontal component was not used to solve for the time. Therefore hang time = 1.01 s