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Eva8 [605]
4 years ago
15

A square weightless frame ABCD with the side a is rotating around the side AB with the constant angular velocity ω1. A uniform d

isk of radius R and mass m is rotating around the frame’s diagonal AC with the constant angular velocity ω2. The center of the disk coincides with the center of the frame. Assuming ω1 = ω2 = ω find
a. The kinetic energy of the system.
b. The magnitude of the torque that needs to be applied to the axis AB to keep it (the axis AB) still.

Physics
1 answer:
Zarrin [17]4 years ago
5 0

Answer:

1) KE of the system = 1/2(Iw^2)

2) the torque T that must be applied to keep it still must be equal to the torque of rotation. This is equal to

T = (Iw^2)/2©

Where;

I = moment of inertia of the body

W = angular velocity of the body

© = angle of rotation in rad

Explanation:

Detailed explanation and calculation is shown in the image below

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R= \frac{\rho L}{A}
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A is the cross-sectional area of the wire

The length of the wire is quadrupled, so if we call L the original length and L' the new length, we can write 
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Similarly, the radius of the wire is doubled (r'=2r), so the new area is
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And if we substitute into the equation, we find that the new resistance of the wire is
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Answer: 26.84 m/s

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