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Firlakuza [10]
4 years ago
5

Ariana is heating a beaker of water. She notices that the water at the bottom

Physics
1 answer:
RSB [31]4 years ago
6 0
B will be the answer ( Radiation)
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A bowler applies 14 N of force to a 4.5 kg bowling<br> ball. Find the ball's acceleration.
brilliants [131]

Answer:

F=m(a)  3.111

Explanation:

So to find the acceleration you would have to reverse the problem, a=F/m

4 0
3 years ago
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Chich expression correctly describes force using Sl units
Zinaida [17]

Answer:1 N = 1 kg·m/s2

Explanation:

5 0
3 years ago
A bock of lead has deminsions of 4.50cm by 5.20cm by 6.00cm, what is the volume
lawyer [7]

Answer:

Look at this picture this is the answer

Explanation:

6 0
3 years ago
Plzzzz urgent <br><br><br>solve this​
Mariana [72]

Answer:

\large{ \tt{☄ \: EXPLANATION}} :

  • Before solving , You'll have to know - When an object starts from the state of rest , in this case , initial velocity ( u ) = 0

  • Notice that we're provided the time ( t ) in minutes. So , first thing we have to do is convert the minutes into seconds. It would be - Time ( t ) = 5 minutes = 5 × 60 sec = 300 sec [ 1 min = 60 sec ]

  • Here , We're provided - Initial velocity ( u ) = 0 , Final velocity ( v ) = 60 m / s , Time taken ( t ) = 300 seconds & We're asked to find out the acceleration ( a ) & distance covered by the jeep ( s ) .

\large{ \tt{♨ \:LET'S \: START}} :

  • Acceleration is defined as the rate of change of velocity. We know :

\large{ \boxed{ \tt{❁ \: ACCELERATION \: (a) =  \frac{FINAL \: VELOCITY(v) - INITIAL \: VELOCITY(u)}{TIME \: TAKEN \: ( \: t \: )}}}}

- Plug the values & then simplify !

\large{ \bf{↬a =  \frac{60 - 0}{300}  =  \frac{60}{300} =  \boxed{ \bold{ \bf{0.2 \: m {s}^{ - 2} }}} }}

  • The acceleration of the jeep is 0.2 m/s²

\large{ \tt{۵ \: AGAIN, \: USING\: SECOND \: EQUATION \: OF \: MOTION}} :

\boxed{ \large{ \bf{✾ \: s =  \frac{u + v}{2}  \times t}}}

- Plug the values & then simplify !

\large{ \bf{↦s =  \frac{0 + 60}{2}  \times 300 =  \boxed{ \bold{ \bf{9000 \: m}}}}}

  • The distance covered by the jeep is 9000 m .

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7 0
3 years ago
A major artery with a 1.7 cm2 cross-sectional area branches into 18 smaller arteries, each with an average cross-sectional area
Alex

Answer:

0.14

Explanation:

Flow rate is the volume flowing through a point at a particular time, in calcuing flow rate we have

Q= v*t

it in terms of Area, we have Q= A*v

Where A= area

v= velocity.

Solving the question , flow rate is constant then

A*v= constant

A(i) v(i)= A(f) v(f)

Where A(i)= initial area= 1.00cm^2

A(f)= final area= 0.400cm^2

V(i) and V(f) are the initial and final velocity respectively and the ratio of the two will gives us the factor

Substitute the values into the equation we have

1 V(i)= 4 V(f)

But we were told that the cross sectional area of 1.00cm^2 branches into 18 smaller arteries.

Then

1 V(i)=0.4 V(f)*(18)

1 V(i)=7.2V(f)

Then if we find the ratio of the velocity, we will get the factor.

V(f)/V(i)= 1/7.2

V(f)/V(i)=0.14

Hence, the factor of the average velocity of the blood reduced when it passes into these branches is 0.14

8 0
3 years ago
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