9514 1404 393
Answer:
671 feet
Step-by-step explanation:
There are a couple of ways to figure this. One is to use a sort of shortcut equation to find the distance traveled (d) by an object when subject to some initial velocity (v) and acceleration (a). Here the acceleration due to gravity is -32 ft/s².
v² = 2ad
d = v²/(2a) = (192 ft/s)^2/(2·32 ft/s²) = 576 ft
This height is in addition to the starting height of 95 ft, so the arrow's maximum height is ...
max height = 95 ft + 576 ft = 671 ft
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Another way to work this problem is to start with the equation for ballistic motion. Filling in the given initial velocity and height, we have ...
h(t) = -16t^2 +192t +95
The time the arrow reaches the maximum height is the time representing the axis of symmetry of the parabola:
t = -(192)/(2(-16)) = 6
Then the maximum height is ...
h(6) = -16·6^2 +192·6 +95 = 671
The maximum height is 671 feet.
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<em>Additional comment</em>
For the standard-form quadratic ...
y = ax^2 +bx +c
The axis of symmetry is ...
x = -b/(2a)
The volume of a cone is V=(1/3)(area of the base)(height)= (1/3)(pi*r^2)(h)
r^2= (d/2)^2 = (d^2)/4. Given: V= 301.44cm^3 and h= 18cm.
r^2= V/[(1/3)(pi)(h)]
r^2= 3V/(pi)(h)
(d^2)/4= 3(301.44)/(3.14)(18)
d^2= 12(301.44)/(3.14)(18)
d^2= 63.967
d= 7.997
d~= 8cm.
Pshhhh she said math negatives I’m pretty sure.
Answer: 2.87 hours
Step-by-step explanation:
There may be a typo in the question because 55 hours in a day is not logical so you must have meant 5.5 hours.
In that case, the hours he will require on the third day would require the distance left to calculate. Get this distance from the first 2 days.
Day 1 distance travelled = Time * Speed
= 5.5 * 66
= 363 miles
Day 2 distance travelled = Time * Speed
= 5.5 * 58
= 319 miles
Total distance remaining
:= 840 - 363 - 319
= 158 miles
Travelling at 55 miles per hour, the time to be taken is:
= Distance remaining / Speed
= 158 / 55
= 2.87 miles per hour