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shtirl [24]
2 years ago
6

O 25 о 50 о 100 X= what

Mathematics
1 answer:
Kruka [31]2 years ago
7 0
What’s the question?
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An arrow is launched upward with a velocity of 192 feet per second from the top of a 95-foot stage. What is the maximum height a
Shalnov [3]

9514 1404 393

Answer:

  671 feet

Step-by-step explanation:

There are a couple of ways to figure this. One is to use a sort of shortcut equation to find the distance traveled (d) by an object when subject to some initial velocity (v) and acceleration (a). Here the acceleration due to gravity is -32 ft/s².

  v² = 2ad

  d = v²/(2a) = (192 ft/s)^2/(2·32 ft/s²) = 576 ft

This height is in addition to the starting height of 95 ft, so the arrow's maximum height is ...

  max height = 95 ft + 576 ft = 671 ft

__

Another way to work this problem is to start with the equation for ballistic motion. Filling in the given initial velocity and height, we have ...

  h(t) = -16t^2 +192t +95

The time the arrow reaches the maximum height is the time representing the axis of symmetry of the parabola:

  t = -(192)/(2(-16)) = 6

Then the maximum height is ...

  h(6) = -16·6^2 +192·6 +95 = 671

The maximum height is 671 feet.

__

<em>Additional comment</em>

For the standard-form quadratic ...

  y = ax^2 +bx +c

The axis of symmetry is ...

  x = -b/(2a)

6 0
3 years ago
The diameter of a cone is X cm the height is 18 cm mThe The height is 18 cm and the volume is 301.44 cm what is x
HACTEHA [7]
The volume of a cone is V=(1/3)(area of the base)(height)= (1/3)(pi*r^2)(h)
r^2= (d/2)^2 = (d^2)/4. Given: V= 301.44cm^3 and h= 18cm.
r^2= V/[(1/3)(pi)(h)]
r^2= 3V/(pi)(h)
(d^2)/4= 3(301.44)/(3.14)(18)
d^2= 12(301.44)/(3.14)(18)
d^2= 63.967
d= 7.997
d~= 8cm.
4 0
3 years ago
What are both of these?
allochka39001 [22]
Pshhhh she said math negatives I’m pretty sure.
3 0
2 years ago
Pablo is on a road trip which will cover a distance of 840 miles. He plans to break the trip up and will complete it over three
Colt1911 [192]

Answer: 2.87 hours

Step-by-step explanation:

There may be a typo in the question because 55 hours in a day is not logical so you must have meant 5.5 hours.

In that case, the hours he will require on the third day would require the distance left to calculate. Get this distance from the first 2 days.

Day 1 distance travelled = Time * Speed

= 5.5 * 66

= 363 miles

Day 2 distance travelled = Time * Speed

= 5.5 * 58

= 319 miles

Total distance remaining

:= 840 - 363 - 319

= 158 miles

Travelling at 55 miles per hour, the time to be taken is:

= Distance remaining / Speed

= 158 / 55

= 2.87 miles per hour

8 0
2 years ago
If i go into an ice cream parlor, and i have the choice of having one of 10 different flavors, with one of 5 different toppings
horrorfan [7]
35 hope this helps with the problem
7 0
3 years ago
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