Question

PLEASE HELP! Find an equation of the line whose intercepts are twice those of the graph of 5y+2x=10.

Answer 1

5y+2x=10y=−25x+2246810−2−4−6−8−10246810−2−4−6−8−10Let's solve for x.5y+2x=10Step 1: Add -5y to both sides.2x+5y+−5y=10+−5y2x=−5y+10Step 2: Divide both sides by 2.2x2=−5y+102x=−52y+5Answer:x=−52y+5

Answer 2

Do make the intercepts twice as big, you simple divide the function by 2, but leave it =10.

The function 5y+2x=10 has intercepts (0,2) and (5,0)

Therefore by dividing by 2 we get 2.5y+x=10 which is your answer. It has intercepts (0,4) and (10,0)