Answer:
ax² + bx + c
Step-by-step explanation:
The form of a quadratic equation that is easy to use when finding the maximum or minimum value of the function is ax² + bx + c.
Suppose a quadratic function:
f(x) = 2x² - 8x + 9
Use ( -b/2a , f(-b/2a) ).
-b/2a
a = 2
b = -8
-(-8)/2(2)
8/4
= 2
f(2) = 2(2)² - 8(2) + 9
f(2) = 2(4) - 8(2) + 9
f(2) = 8 - 16 + 9
f(2) = 1
The minimum value of this quadratic function is (2, 1).
It represents a minimum value because a > 0.
9514 1404 393
Answer:
y = 5x - 7
Step-by-step explanation:
We can make an equation for the perpendicular line by swapping the x- and y-coefficients, negating one of them. Then we can use that form with the given point to see what the constant is.
10x -2y = ...
Removing a common factor of 2 gives ...
5x -y = 5(2) -(3) = 7 . . . . using (x, y) = (2, 3), we can find the constant
Solving for y, we get ...
5x -7 = y . . . add y-7
y = 5x -7 . . . write in the desired form
A. Y would be 14 since 2w would equal -8, and -8+14=6.
B. Y would be -14 because 2w would equal 20 and 20+(-14)=6
Answer:
3 and 9
Step-by-step explanation:
3 * 24 = 72
9 * 8 = 72
3 * 15 = 45
9 * 5 = 45