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Dmitrij [34]
3 years ago
9

What is the solution set of 4x=y and 2x^2-y=0

Mathematics
1 answer:
balandron [24]3 years ago
5 0
The equation 4x = y is solve for y so we can substitute the expression 4x for y in the other equation.

2x² - (4x) = 0 ← Substituted 4x for y...Hug'em when you plug'em (use ( )s)
2x² - 4x = 0 ← prepare to factor
2x(x - 2) = 0 ← factored out the GCF
2x = 0 or x - 2 = 0 ← zero product property
x = 0 or x = 2 ← solved each mini equation
If x = 0, then y = 4(0) = 0. (0, 0) is a solution
If x = 2, then y = 4(2) = 8. (2, 8) is a solution
The solution set is {(0,0), (2,8)}
You might be interested in
What is the approximate probaitly that next year tempereture (year 16) will be in the 90s
Liula [17]

Answer:

50/50

Step-by-step explanation:

5 0
3 years ago
F(x)=x^4-5x^2-6x-10 is divided by x-3
LiRa [457]

Answer:

Step-by-step explanation:

STEP

1

:

           10

Simplify   ——

           x

Equation at the end of step

1

:

                       10

 ((((x4)-(5•(x2)))-6x)-——)-3

                       x

STEP

2

:

Equation at the end of step

2

:

                           10    

 ((((x4) -  5x2) -  6x) -  ——) -  3

                           x      

STEP

3

:

Rewriting the whole as an Equivalent Fraction

3.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  x  as the denominator :

                     x4 - 5x2 - 6x     (x4 - 5x2 - 6x) • x

    x4 - 5x2 - 6x =  —————————————  =  ———————————————————

                           1                    x        

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

STEP

4

:

Pulling out like terms

4.1     Pull out like factors :

  x4 - 5x2 - 6x  =   x • (x3 - 5x - 6)

Polynomial Roots Calculator :

4.2    Find roots (zeroes) of :       F(x) = x3 - 5x - 6

Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  -6.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,2 ,3 ,6

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -2.00    

     -2       1        -2.00        -4.00    

     -3       1        -3.00        -18.00    

     -6       1        -6.00        -192.00    

     1       1        1.00        -10.00    

     2       1        2.00        -8.00    

     3       1        3.00        6.00    

     6       1        6.00        180.00    

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

4.3       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x • (x3-5x-6) • x - (10)     x5 - 5x3 - 6x2 - 10

————————————————————————  =  ———————————————————

           x                          x        

Equation at the end of step

4

:

 (x5 - 5x3 - 6x2 - 10)    

 ————————————————————— -  3

           x              

STEP

5

:

Rewriting the whole as an Equivalent Fraction

5.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  x  as the denominator :

        3     3 • x

   3 =  —  =  —————

        1       x  

Checking for a perfect cube :

5.2    x5 - 5x3 - 6x2 - 10  is not a perfect cube

Trying to factor by pulling out :

5.3      Factoring:  x5 - 5x3 - 6x2 - 10

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -6x2 - 10

Group 2:  x5 - 5x3

Pull out from each group separately :

Group 1:   (3x2 + 5) • (-2)

Group 2:   (x2 - 5) • (x3)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

5.4    Find roots (zeroes) of :       F(x) = x5 - 5x3 - 6x2 - 10

    See theory in step 4.2

In this case, the Leading Coefficient is  1  and the Trailing Constant is  -10.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,2 ,5 ,10

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -12.00    

     -2       1        -2.00        -26.00    

     -5       1        -5.00       -2660.00    

     -10       1       -10.00       -95610.00    

     1       1        1.00        -20.00    

     2       1        2.00        -42.00    

     5       1        5.00        2340.00    

     10       1        10.00       94390.00    

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

5.5       Adding up the two equivalent fractions

(x5-5x3-6x2-10) - (3 • x)      x5 - 5x3 - 6x2 - 3x - 10

—————————————————————————  =  ————————————————————————

            x                            x            

Polynomial Roots Calculator :

5.6    Find roots (zeroes) of :       F(x) = x5 - 5x3 - 6x2 - 3x - 10

    See theory in step 4.2

In this case, the Leading Coefficient is  1  and the Trailing Constant is  -10.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,2 ,5 ,10

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -9.00    

     -2       1        -2.00        -20.00    

     -5       1        -5.00       -2645.00    

     -10       1       -10.00       -95580.00    

     1       1        1.00        -23.00    

     2       1        2.00        -48.00    

     5       1        5.00        2325.00    

     10       1        10.00       94360.00    

Polynomial Roots Calculator found no rational roots

Final result :

 x5 - 5x3 - 6x2 - 3x - 10

 ————————————————————————

            x            

3 0
3 years ago
Drag steps in the given order to evaluate this<br> expression.<br> (-5)(2) – 2(-3) + 3
sesenic [268]

Answer:

-1

Step-by-step explanation:

using PEDMAS(parentheses, exponents, division, multiply, addition, subtraction) to solve the problem

First, multiply (-5)(2) and 2(-3)

(-5)(2) – 2(-3) + 3

=-10-(-6)+3

=-10+6+3

add -10+6

-4+3

Add -4+3

-4+3

=-1

Therefore, (-5)(2) – 2(-3) + 3 is equal to -1

4 0
3 years ago
What does a trillion look like in numbers?
mixer [17]
100000000
8 zeroes in a trillion
4 0
3 years ago
the ratio of dogs to cats at the pet store is 1:4.if the pet shop has 7 dogs,how many cats does it have ?
slamgirl [31]
1:4=\frac{1}{4}\\\\d-number\ of\ dogs;\ c-number\ of\ cats\\\\d:c=1:4\to\frac{d}{c}=\frac{1}{4}\\\\d=7\ therefore\\\\\frac{7}{c}=\frac{1}{4}\ \ \ \ |cross\ multiply\\\\1\cdot c=7\cdot4\\\\\boxed{c=28}\leftarrow answer
6 0
3 years ago
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