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Dmitrij [34]
3 years ago
9

What is the solution set of 4x=y and 2x^2-y=0

Mathematics
1 answer:
balandron [24]3 years ago
5 0
The equation 4x = y is solve for y so we can substitute the expression 4x for y in the other equation.

2x² - (4x) = 0 ← Substituted 4x for y...Hug'em when you plug'em (use ( )s)
2x² - 4x = 0 ← prepare to factor
2x(x - 2) = 0 ← factored out the GCF
2x = 0 or x - 2 = 0 ← zero product property
x = 0 or x = 2 ← solved each mini equation
If x = 0, then y = 4(0) = 0. (0, 0) is a solution
If x = 2, then y = 4(2) = 8. (2, 8) is a solution
The solution set is {(0,0), (2,8)}
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fgiga [73]

Answer:

7 weeks

Step-by-step explanation:

80 ÷ 20 = 4

She over those four week she makes 17 per week. So,

17 × 4 = 68

Next, divide the product by 20:

68 ÷ 20 = 3.4

But 3.4 is only 3 full weeks so then its 3.

Lastly, add the 3 weeks we just solved for the the 4 weeks from before and you get 7 weeks.

So, Anna will be able to supply the "Unique" store for 7 weeks.

I HOPE I HELPED!!!!!!!!!! :))))))

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3 years ago
Find the missing side of the triangle <br>​
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Using the Pythagorean theorem where:
b^2 = c^2 - a^2
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8 0
3 years ago
I- i just need help at this point...
chubhunter [2.5K]

Answer:

(2.8-3.5)/3.5=-.2 (100)=20%

Percent error is 20%

formula to fin percent error is ((approx-exact)/exact)(100)

Step-by-step explanation:

5 0
3 years ago
What is 1/5 expressed as a percent
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4 0
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3 years ago
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