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geniusboy [140]
3 years ago
15

Write an equation of the line that passes through (-5,3) and is parallel to the line y=-x+3

Mathematics
1 answer:
Marat540 [252]3 years ago
5 0

Answer:

y = -x - 2

Step-by-step explanation:

Note that the given line, y=-x+3, has a slope of -1.  Any new line parallel to this one must also have that slope, -1:

y=-x+3 becomes 3 = -(-5) + C, where C is the y-intercept:

3 = 5 + C, or C = -2

Thus, the desired equation of this new line is y = -x - 2

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4+ 3x (10 - 2^3)

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In the diagram, GH bisects FGI. A. Solve for x and find m FGH. B. Find m HGI. C.find m FGI. A. X=_(simplify your answer)
Sophie [7]

Answer:

Part A) x=9 and m∠FGH=29°

Part B) m∠HGI=29°

Part C) m∠FGI=58°

Step-by-step explanation:

Part A) Solve for x and find m∠FGH

we know that

m∠FGI=m∠FGH+m∠HGI

If GH bisects FGI

then

m∠FGH=m∠HGI

substitute the values

4x-7=5x-16

solve for x

5x-4x=16-7

x=9

m∠FGH=4x-7

m∠FGH=4(9)-7=29°

Part B) Find the measure of angle HGI

m∠HGI=5x-16

Remember that

m∠FGH=m∠HGI

Verify

m∠HGI=5(9)-16=29° -----> is correct

Part C) Find the measure of angle FGI

m∠FGI=m∠FGH+m∠HGI

substitute the values

m∠FGI=29°+29°=58°

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