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iragen [17]
2 years ago
10

What's the range of the function y= -2(2)^x+2

Mathematics
1 answer:
Aleksandr [31]2 years ago
4 0

Answer:

Step-by-step explanation:

Simply substitute the x and y values into the equation, Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.  

Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.  

y=-2(2)(-infity)+2

y=2

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