What's the range of the function y= -2(2)^x+2
1 answer:
Answer:
Step-by-step explanation:
Simply substitute the x and y values into the equation, Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.
Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.
y=-2(2)(-infity)+2
y=2
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Answer:
21
Step-by-step explanation:
5(21)-12=93
3(21)+30=93
The area of a square is:
A=s^2, where s is a side length so
A=4^2
A=16m^2
0 = -16t² + 36t + 4
0 = -8t² + 18t + 2 ← Complete the square to solve
-8(t² - 9t/2) = -2
8(t² - 9t/4 + 81/64) = 2 + 81/8
8(t - 9/8)² = 97/8
(t - 9/8)² = 97/64
t - (t = 0)
(h = 0) at:
<span>t = (9 + √97)/8 ≅ 2.356 seconds
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Answer:
6.70820 or the square root of 45
Step-by-step explanation:
6^2 = 36
3^2 = 9
36 + 9 = 45
