What's the range of the function y= -2(2)^x+2
1 answer:
Answer:
Step-by-step explanation:
Simply substitute the x and y values into the equation, Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.
Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.
y=-2(2)(-infity)+2
y=2
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