Well to find the volume of a pyramid, you take the base (12mm) times the height (15mm) times 1/3 to get an answer of 60mm squared.
Hope this helped.
Answer:
The 95% confidence interval on the true proportion of helmets of this type that would show damage from this test is (0.169, 0.397).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval on the true proportion of helmets of this type that would show damage from this test is (0.169, 0.397).
A.
To get dividend per share, we need to divide total dividend by total numbers of shares outstanding.
Dividend per share =
dollars.
B.
Since per share you get $0.8, for 100 shares you will get
dollars.
Also, that is
percent of the total dividends.
ANSWER:
A. $0.8 per share
B. $80 (and that is 0.2% of total dividend)
D because you have to use absolute value to solve.
Answer:
There is a 25.14% probability that the order will not be met during a month.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean \mu and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
.
The order will not be met if
. So we find the pvalue of Z when
, and subtract 1 by this value.



has a pvalue of 0.7486.
So there is a 1 - 0.7486 = 0.2514 = 25.14% probability that the order will not be met during a month.