My best guess would be a biker they love motor bike they wear leather jackets and ride in groups this is the only thing i could think of
~ thanks ~
Answer:
PART ONE
- import java.util.Scanner;
- public class CountToLimit {
- public static void main(String[] args) {
- Scanner scnr = new Scanner(System.in);
- int countLimit = 0;
- int printVal = 0;
- // Get user input
- System.out.println("Enter Count Limit");
- countLimit = scnr.nextInt();
- do {
- System.out.print(printVal + " ");
- printVal = printVal + 1;
- } while ( printVal<=countLimit );
- System.out.println("");
- return;
- }
- }
PART TWO
- import java.util.Scanner;
- public class NumberPrompt {
- public static void main (String [] args) {
- Scanner scnr = new Scanner(System.in);
- System.out.print("Your number < 100: ");
- int userInput = scnr.nextInt();
- do {
- System.out.print("Your number < 100: ");
- userInput = scnr.nextInt();
- }while (userInput>=100);
- System.out.println("Your number < 100 is: " + userInput);
- return;
- }
- }
Explanation:
In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14
In part 2, A do....while loop that will repeatedly prompt user to enter a number less than 100 is created. from line 7 to line 10
Assuming the data was encrypted with YOUR public key, you'll need YOUR private key to decrypt it. That's answer e.
a and b are not solutions by themselves, of course you need to use the decryption algorithm, but a key goes with it.
c would be about symmetric encryption, but this is asymmetric, so different keys are used for encryption and decryption
d is possible, but it would mean anyone can decrypt it (after all the key is public), so then there's no point in encrypting it in the first place.
So e is the only logical answer.
<span>Exploit -</span> An attack that takes advantage of a system vulnerability, often<span> due to a combination of one or more improperly configured services.</span>
