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Vaselesa [24]
1 year ago
13

A customer uses an app to order pizza for delivery. Which component includes

Computers and Technology
1 answer:
ankoles [38]1 year ago
5 0

~frestoripongetosarangeou

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Build three classes that conform to the following interfaces. Use arrays in creating your classes (e.g., do not use the built-in
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Explanation:

public class ArrayList {

private Object[] array = new Object[1];

/**

 * Places new element at location

 * @param c, element to be inserted

 * @param i, location it is to be placed

 */

public void insert(char c, int i) {

 if(i>this.size()){

  System.out.println("Index "+i +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(i){

     case 0:{

      other[0] = c;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<i;j++)

       other[j] = this.array[j];

      other[i] = c;

      for(int k=i+1;k<this.array.length;k++)

       other[k] = this.array[k-1];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

}

 

/**

 * Places new element at location

 * @param object, element to be inserted

 * @param index, location it is to be placed

 */

void insert(Object object, int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(index){

     case 0:{

      other[0] = object;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      other[index] = object;

      for(int k=index+1;k<this.array.length;k++)

       other[k] = this.array[k];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

}

 

/**

 * Removes element at index

 * @param index, location to remove

 * @return temp, object removed

 */

Object remove(int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 Object temp = this.array[index];

 int count = 0;

 try {

  Object[] other = new Object[this.array.length-1];

  switch(index){

     case 0:{

      other[0] = this.array[1];

      for(int j=1;j<this.size();j++)

       other[j] = this.array[j+1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      for(int k=index;k<this.size();k++)

       other[k] = this.array[k+1];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

 return temp;

}

 

/**

 * Copies the array to a new array twice the size.

 */

public void largerArray(){

 Object[] other = new Object[this.array.length*2];

 System.arraycopy(this.array, 0, other, 0, this.array.length);

 this.array = other;

}

 

/**

 * @return true if there are null elements

 */

public boolean isEmpty() {

 boolean bool = true;

 for (Object element : this.array) {

  if(element!=null){

   bool = false;

   break;

  }

  else{

   bool = true;

   break;

 }

 }

 return bool;

}

 

/**

 * Determines the real length of the array

 * @return length of non-null elements

 */

public int size(){

 int count = 0;

 for(int i=0;i<this.array.length;i++){

  if(this.array[i]==null)

   continue;

  else

   count++;

 }

 return count;

}

 

/**

 * Converts array to string.

 * @return the Array as a string

 */

public String toString(){

 String string = "";

 for(int i=0;i<this.size();i++){

  if(i<this.size()-1)

   string += this.array[i]+", ";

  else

   string += this.array[i];

 }

 return string;

}

 

/**

 * Similar to get, imput the character, retrieve index.

 * @param object, what we're looking for

 * @return index

 */

int indexOf(Object object){

 int index = -1;

 for(int i=0;i<this.array.length;i++){

  if(this.array[i]==(object))

   index = i;

  else continue;

 }

 return index;

}

 

/**

 * @param object, Arraylist tyoe

 * @return true, if the elements of the arrays are equivalent.

 */

public boolean equals(ArrayList object){

 boolean bool = false;

 int thisLength = this.array.length;

 int objectLength = object.array.length;

 if(thisLength > objectLength){

  for(int i=0;i<this.array.length;i++)

   if(this.array[i] == object.array[i])

    bool = true;

   else{

    bool = false;

    break;

   }

 }

 else{

  for(int i=0;i<object.array.length;i++)

   if(this.array[i] == object.array[i])

    bool = true;

   else{

    bool = false;

    break;

   }

 }

 return bool;

}

 

/**

 * Getter to check what is at an index

 * @param index, location

 * @return the character at this position

 */

Object get(int index){

 return this.array[index];

}

}

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Which two features could be added to a game using an "if () then " block
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The two features could be added to a game using an "if () then " block are:

  • Using nested If Then blocks.
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<h3>What does the If Then block mean?</h3>

The If Then block is known to be the outputs one of  a given two values, that is as a result of  the value of a Boolean input.

Note that  the input value  is very important and as such, The two features could be added to a game using an "if () then " block are:

  • Using nested If Then blocks.
  • Checks the specific Bid quantity for the instrument.

Learn more about game  from

brainly.com/question/1786465

#SPJ1

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