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4 years ago

What is the total rounded to the nearest tenth of 94.23

2 answers:

5 0

See 94.23 is the number you are rounding.

94.23 the 2 is in the tenth place so you look at the next number 3 since it’s less then 5 the total rounded to the nearest tenth would be 94.2 because you take off the 3

andrey2020 [161]4 years ago

3 0

The total is 94.2.

Hope this helps!

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3 years ago

Emily purchased a couch, loveseat, in the chair for $2000. The Loveseat cost twice as much as the chair, and the couch cost $600

romanna [79]

Answer:

Chair $280

Loveseat $560

Couch $ 1,160

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chair = x

loveseat=2x

couch = 2x + 600

x +2x + 2x +600 = 2000

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5x =1400 divide by 5

x = $280

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3 years ago

One percent of all individuals in a certain population are carriers of a particular disease. A diagnostic test for this disease

Lynna [10]

Answer:

(1) The probability that an individual who tests negative does not carry the disease is 0.9709.

(2) The specificity of the test is 98%.

Step-by-step explanation:

Denote the events as follows:

X = a person carries the disease

Y = the test detected the disease.

Given:

$P(X) = 0.01\\P(Y|X)=0.93\\P(Y|X^{c})=0.02$

The probability of a person not carrying the disease is:

$P(X^{c})=1-P(X)=1-0.01=0.99$

The probability that the test does not detects the disease when the person is carrying it is:

$P(Y^{c}|X)=1-P(Y|X)=1-0.93=0.07$

The probability that the test does detects the disease when the person is not carrying it is:

$P(Y^{c}|X^{c})=1-P(Y|X^{c})=1-0.02=0.98$

(1)

Compute the probability that an individual who tests negative does not carry the disease as follows:

$P(X^{c}|Y^{c})=\frac{P(Y^{c}|X^{c})P(X^{c})}{P(Y^{c}|X^{c})P(X^{c})+P(Y^{c}|X)P(X)} \\=\frac{(0.98\times 0.99)}{(0.98\times 0.99)+(0.07\times 0.01)} \\=0.9709$

Thus, the probability that an individual who tests negative does not carry the disease is 0.9709.

(2)

By specificity it implies that how accurate the test is.

Compute the probability of negative result when the person is not a carrier as follows:

$P(Y^{c}|X^{c})=1-P(Y|X^{c})=1-0.02=0.98$

Thus, the specificity of the test is 98%.

8 0

4 years ago