First term (a1) is -1
recursive formula goes like this
is the nth term
is the term before that
we normally have
we see each term is multipying by -3 to get next one
so that would be
where a1=-1
the 3rd option is correct except that it is the explicit formula
so answer is 2nd one
One possible solution is
f(x) = x^4
g(x) = x-3
Since
f(x) = x^4
f(g(x)) = ( g(x) )^4
f(g(x)) = ( x-3 )^4
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Another possible solution could be
f(x) = x^2
g(x) = (x-3)^2
Because
f(x) = x^2
f(g(x)) = ( g(x) )^2
f(g(x)) = ( (x-3)^2 )^2
f(g(x)) = (x-3)^(2*2)
f(g(x)) = (x-3)^4
Answer:
Step-by-step explanation:
Unclear. Did you mean f(x) = 2^(x + 3)? If so, the parentheses are mandatory.
Assuming that f(x) = 2^(x + 3) is correct, then:
a) f(2) = 2^(2 + 3) = 2^5 = 32
b) f'(x) = 2^(x + 3)*(x + 3)' = 2^(x + 3)(1) = 2^(x + 3)
c) f"(x) = 2^(x + 3) (same as in (b)), so that:
f"(12) = 2^15
Answer:
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
Exact Form:
x=1/5,3
Decimal Form:
x=0.2,3
62/949+ 297i/949 is the answer to this problem
