Answer:
Explanation:
Part D
For d, the very first thing you need to do is figure out which one of the steps you are going to use. You have 2 in b^2 + 2, so even if b = 0 the two still matters. It means that you use f(x) = -x + 3 because that's what you use when you have 2 or above.
The second thing you have to realize is that f(x) = -x + 3 has the meaning of what ever you see on the left in the place of x, you put on the right wherever there is an x.
In this case f(b^2 + 2) = -b^2 - 2 + 3 = 1 - b^2
I'm not sure enough to give you an answer for the domain and range, not this time of night.
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