Question

when angles are complementary,the sum of their measures is 90 degrees.Two complementary angles have measure of 2x-10 degrees and l3x-10 degrees.Find the measures of each angle.

Answer 1

Not sure if 13x-10 or 3x-10 since that is an 'l' so therefor I will solve for both
they add to 90 so add the  2 angles
if 13x-10 go to AAAAAAAA
if 3x-10 then go to BBBBBBBB




AAAAAAAAAAAAAAAAAAAAAAA
2x-10+13x-10=90
group like terms
2x+13x-10-10=90
addd liket erms
15x-20=90
add 20 to  both sides
15x=110
divide both sides by 15
x=22/3
subsitute
2x-10
2(22/3)-10
44/3-10
14 and 2/3-10
4 and 2/3 is one angle
then subtract the other one
90-4 and 2/3=85 and1/3
the angles are 4 and 2/3 and 85 and 1/3





BBBBBBBBBBBBBBBB
2x-10 and 3x-10
add
2x-10+3x-10=90
gropu liek terms
2x+3x-10-10=90
add likke terms
5x-20=90
add 20
5x=110
divide y 5
x=22
subsitute
2(22)-10
44-10
34
subtract
90-34=56
the angles are 34 and 56 degrees


I would go with 34 and 56 because you sometimes deal with whole numbers more in math

Answer 2

Since the two angles have a sum of 90 degrees, we can add the two expressions together and set it equal to 90.
$2x-10+13x-10=90\\15x-20=90\\15x=110\\x=22/3\\2(22/3)-10=14/3\\90-14/3=256/3$