Answer:
= −0.26
= 0.4219
Step-by-step explanation:
Given:
Sample1: 98.1 98.8 97.3 97.5 97.9
Sample2: 98.7 99.4 97.7 97.1 98.0
Sample 1 Sample 2 Difference d
98.1 98.7 -0.6
98.8 99.4 -0.6
97.3 97.7 -0.4
97.5 97.1 0.4
97.9 98.0 -0.1
To find:
Find the values of and
d overbar ( ) is the sample mean of the differences which is calculated by dividing the sum of all the values of difference d with the number of values i.e. n = 5
= ∑d/n
= (−0.6 −0.6 −0.4 +0.4 −0.1) / 5
= −1.3 / 5
= −0.26
s Subscript d is the sample standard deviation of the difference which is calculated as following:
= √∑(
- )²/ n-1
=
√ 
= √ (−0.6 − (−0.26
))² + (−0.6 − (−0.26))² + (−0.4 − (−0.26))² + (0.4 −
(−0.26))² + (−0.1 − (−0.26))² / 5−1
= 
= 
= 
= 0.4219
= 0.4219
Subscript d represent
μ
represents the mean of differences in body temperatures measured at 8 AM and at 12 AM of population.
Answer:
The slope is 5/-2.
Step-by-step explanation:
Slope is y1-y2 over m1-m2 (rise over run). The first ordered pair is -2 (m1) and 11 (y1). We then subtract the second ordered pair (4 (m2) and -4 (y2)) from the first.
11 - (-4) = 11 + 4 = 15
-2 - 4 = -6
Remember, slope is rise over run (y over x), so the slope is 15/-6. Now, we must simplify. 15/-6 = 5/-2
Dean went wrong because he thought that slope was run over rise (x over y). If he had switched the two numbers, his answer would have been correct.
Y= arcsin(x) is equivalent to sin(y) = x
we know that -1≤x+1, hence the range of y is: -π/2≤y≤+π/2
Step-by-step explanation:
m<AEC= 180-152= 28°
m<CEB= 180-28=152°
m<FEC= 90+28=118°
W-5=5
W= 5+5 (bringing -5 to the other side, it becomes +5)
At last, W=10.
