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Nadusha1986 [10]
3 years ago
8

In an upcoming election, the student body will elect a president, vice president, secretary and treasurer.

Mathematics
1 answer:
Vladimir [108]3 years ago
6 0
25*24*23*22=303600

each multiplicand is just the number of people remaining to choose from at that point in the selection process...
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Samantha owes her father $7 she just got paid $5.50 for babysitting if she gives that money to her dad how much will she still o
zalisa [80]

Answer:

$1.5

Step-by-step explanation:

$7- 5.50= 1.5

5 0
3 years ago
8 and 4 / 9 divided by 2 and 1 / 9<br><br><br> 10 points<br><br> Please show work
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3 years ago
A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor
Leno4ka [110]

Answer:

C=120/2=60

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

P(X=0)=0.98^20

P(X=0)=0.668

P(X=1)=0.02*20*0.98^19

P(X=1)=0.272

P(X=2)=0.02^2*20*0.98^18

P(X=2)=0.053

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

C=120/2=60

7 0
3 years ago
The graph of h(x) is shown. Graph of h of x that begins in quadrant two and decreases rapidly following the vertical line which
fgiga [73]

Answer:

<u>x-intercept</u>

The point at which the curve <u>crosses the x-axis</u>, so when y = 0.

From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)

<u>y-intercept</u>

The point at which the curve <u>crosses the y-axis</u>, so when x = 0.

From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)

<u>Asymptote</u>

A line which the curve gets <u>infinitely close</u> to, but <u>never touches</u>.

From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5

(Please note:  we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).

5 0
2 years ago
Read 2 more answers
Simplify: 3 square root 216<br> A. 8<br> B. 16<br> C. 6<br> D. 2
zysi [14]

Answer:

6

Step-by-step explanation:

Use a calculator

4 0
2 years ago
Read 2 more answers
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