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Serga [27]
3 years ago
13

Niki makes the same payment every two months to pay off his $61,600 loan. The loan has an interest rate of 9.84%, compounded eve

ry two months. If Niki pays off his loan after exactly eleven years, how much interest will he have paid in total? Round all dollar values to the nearest cent.
Mathematics
2 answers:
mars1129 [50]3 years ago
6 0
After a series of calculations, I found out that the interest he has to pay in total would be <span>$117,484.77.

You might use my answer in reviewing by using your solution also.

I hope my answer has come to your help. God bless and have a nice day ahead!
</span>
MissTica3 years ago
6 0

Answer:

$39,695.48

Step-by-step explanation:

Here, the present value of the annuity is given.

Here, PV = $61,600

P is the periodic payment.

r = 9.84% or 0.0984

t = number of payments in a year = 6

n = 11 years

61600= P(1-(1+0.0984/6)^{-(11\times6)})/ (0.0984/6)

=> 61600\times0.0164 =P(1 - (1.0164)^{-66})

=>P =1010.24/0.658231

= 1534.78

So, Niki is paying $1,534.78 at every two months interval for eleven years.

Hence, total payment made by Niki will be = 11\times6\times1534.78 = $101295.48

So, interest paid = 101295.48-61600 = $39,695.48

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olga2289 [7]

Given:

The equation of the curve is:

y=2x^3-5x+1

To find:

The gradient (slope) of the given curve at point (2,7).

Solution:

We have,

y=2x^3-5x+1

Differentiate the given equation with respect to x.

y=2(3x^2)-5(1)+(0)

y'=6x^2-5

Now we need to find the value of this derivative at (2,7).

y'_{(2,7)}=6(2)^2-5

y'_{(2,7)}=6(4)-5

y'_{(2,7)}=24-5

y'_{(2,7)}=19

Therefore, the gradient (slope) of the given curve at point (2,7) is 19.

8 0
3 years ago
What is the greatest common factor of 20x6y+40x4y2−10x5y5 ?
mestny [16]
The greatest common factor: 20x^6y 40x^4y^2 10x^5y^5 is 10x^4y.
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8 0
4 years ago
Consider a data set containing the following values: 70 65 71 78 89 68 50 75 The mean of the preceding values is 70.75. The devi
Leokris [45]

Answer:

If this is the sample data, the sample variance is 125.07 and the sample standard deviation is 11.18

If this is a population data, the population variance is 109.44 and the population standard deviation is 10.46

Step-by-step explanation:

We are given the following data-set:

70, 65, 71, 78, 89, 68, 50, 75

Deviations from the mean

–0.75, –5.75 , 0.25, 7.25, 18.25, –2.75, –20.75, 4.2

Sample size, n = 8

Sample:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.

Sum of squares of differences =

0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5

s = \sqrt{\dfrac{875.5}{7}} = 11.18

\text{ Sample variance} = s^2 = 125.07

Population:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.

Sum of squares of differences =

0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5

\sigma = \sqrt{\dfrac{875.5}{8}} = 10.46

\text{ Population variance} = \sigma^2 = 109.44

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I need an example problem for algebra 1
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Answer:

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Answer: So if its a sphere the answer its 7238.2.

If its a cylinder the answer is 371.7.

If its a triangular shape the answer is  

123.9.

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