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kotegsom [21]
3 years ago
5

How does making a frequency table or line plot help you see which value occurs most often in a data set?

Mathematics
1 answer:
klemol [59]3 years ago
4 0

Answer:

A frequency table and a line plot show which value occurs most often. this is done by labeling every value. The person can clearly see the organized layedout numbers in a frequency table or line plot.

Step-by-step explanation:

If you have any questions feel free to ask in the comments.

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Find the measure of the arc or angle indicated.
Shkiper50 [21]

9514 1404 393

Answer:

  arc AC = 63°

Step-by-step explanation:

Arc BC is twice the measure of inscribed angle BAC, so is ...

  arc AC = 2×89° = 178°

The remaining arc of the circle is the difference between 360° and the sum of the other two.

  arc AC = 360° -119° -178°

  arc AC = 63°

4 0
3 years ago
What is 1/2 times 1/2 times 2 times 12
4vir4ik [10]

Answer:

6

Step-by-step explanation:

1/2 * 1/2 * 2 * 12 =

1/2 * 12 (because the 1/2 and 2 cancel out, as they form 1) =

6

8 0
3 years ago
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I DON'T WANT TO GO TO SUMMER SHCOOL, IF I FAIL I GET SUMMER SHCOOL, PLEASE HELP, IF YOU HAVE ANY KNOWLEDGE ON THIS TEACH ME OR S
jenyasd209 [6]

Answer:

B. 225 π sq. units

Step-by-step explanation:

the diameter of circle = √18²+24²

=√324+576=√900 = 30

the radius = ½×30=15

the area of circle =

π × 15² = π × 225 = 225 π sq. units

8 0
3 years ago
What is the surface area of the figure?
likoan [24]
We can split it up into a net
actually, here is a hack

notice that indented side?
we can take the plane and push it so it makes 4 sides, neat

ok, so we now just have 4 normal sides and 2 L shapes

L shape can be cut into 2 rectangles
5 by 5 and 5 by 10 so total of 75 is the L
2 L's so
2*75=150

the sides
4 of them
they all are 10 by 3
10*3*4=120

toatl is 150+120=270

answer is A

3 0
3 years ago
Read 2 more answers
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
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