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3 years ago

Identify the first term of the algebraic expression. Indicate whether the term is a variable or a constant term.

Mathematics

2 answers:

Naya [18.7K]3 years ago

5 0

Answer:5

Step-by-step explanation:

krok68 [10]3 years ago

3 0

Answer:

Someone text me on sc queenalyssa_05

Step-by-step explanation:

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Precal. Find the sum. Show every step you took to get to your answer. I will give brainliest if you are correct and show all wor

Ymorist [56]

Answer:

I think your forgot to add some parts of this question, because you can't do anything with this except simplify it down a little maybe. But, I will provide the simplified version of this.

$\frac{x-4}{x^2-2x}+\frac{4}{x^2-4}$

= $\frac{x-4}{x\left(x-2\right)}+\frac{4}{x^2-4}$

= $\frac{x-4}{x\left(x-2\right)}+\frac{4}{\left(x+2\right)\left(x-2\right)}$

= $\frac{\left(x-4\right)\left(x+2\right)}{x\left(x-2\right)\left(x+2\right)}+\frac{4x}{\left(x+2\right)\left(x-2\right)x}$

= $\frac{\left(x-4\right)\left(x+2\right)+4x}{x\left(x-2\right)\left(x+2\right)}$

= $\frac{x+4}{x\left(x+2\right)}$

Step-by-step explanation:

Hope this helped!

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Solve 3x2 + 4x = −5.

Alla [95]

Move the -5 over by adding 5 to both sides
3x^2+4x+5=0
must use quadratic formula

for an equation in the form
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

a=3
b=4
c=5

x= $\frac{-4+/- \sqrt{4^2-4(3)(5)} }{2(3)}$
x= $\frac{-4+/- \sqrt{16-60} }{6}$
x= $\frac{-4+/- \sqrt{-44} }{6}$
x= $\frac{-4+/- 2\sqrt{-11} }{6}$
remember that√-1=i
x= $\frac{-4+/- 2i\sqrt{-11} }{6}$
x= $\frac{-2+/- i\sqrt{-11} }{3}$

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3 years ago