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scoundrel [369]
3 years ago
12

Find all real zeros of the function y = 3x + 1.

Mathematics
1 answer:
murzikaleks [220]3 years ago
4 0

Answer:

-\dfrac{1}{3}

Step-by-step explanation:

The given function is

y=3x+1

We need to find all real zeros of the given function.

Equate y=0, to find all real zeros of the given function.

3x+1=0

Subtract 1 from both sides.

3x+1-1=0-1

3x=-1

Divide both sides by 3.

\dfrac{3x}{3}=\dfrac{-1}{3}

x=-\dfrac{1}{3}

Therefore, the real zero of the function is -1/3.

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