Question

Find all real zeros of the function y = 3x + 1.

Answer 1

Answer:

$-\dfrac{1}{3}$

Step-by-step explanation:

The given function is

$y=3x+1$

We need to find all real zeros of the given function.

Equate y=0, to find all real zeros of the given function.

$3x+1=0$

Subtract 1 from both sides.

$3x+1-1=0-1$

$3x=-1$

Divide both sides by 3.

$\dfrac{3x}{3}=\dfrac{-1}{3}$

$x=-\dfrac{1}{3}$

Therefore, the real zero of the function is -1/3.