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3 years ago

13

Explain how estimation helps you to place the decimal point when multiplying 3.9 x 5.3 ?

2 answers:

Marina CMI [18]3 years ago

3 0

Well the answer to that is 20.67.
Also, you can simply find this out by placing the decimal as you solve the problem, meaning as when you solve like this
3.9
x5.3
--------
.
Drag the decimal down.

Nimfa-mama [501]3 years ago

3 0

If you round 3.9 to 4 and 5.3 to 5 you can easily multiply those numbers together and get 15.

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A pyramid has a square base with sides of length s. The height of the pyramid is equal to - of the length of a side on the base.

Vera_Pavlovna [14]

<h3><u>Question:</u></h3>

A pyramid has a square base with sides of length s. The height of the pyramid is equal to 1/2 of the length of a side on the base. Which formula represents the volume of the pyramid?

<h3><u>Answer:</u></h3>

<em><u>The formula represents the volume of the pyramid is:</u></em>

$V=\frac{1}{6}s^3$

<h3><u>Solution:</u></h3>

<em><u>The volume of square pyramid is given by formula:</u></em>

$V = \frac{1}{3} a^2h$

Where, "h" is the height of pyramid

"a" is the length of side of base

Here given that, pyramid has a square base with sides of length s

Therefore,

a = s

The height of the pyramid is equal to 1/2 of the length of a side on the base

$h = \frac{1}{2} \times s\\\\h = \frac{s}{2}$

<em><u>Thus the volume of pyramid becomes:</u></em>

$V = \frac{1}{3} \times s^2 \times \frac{s}{2}\\\\V = \frac{s^3}{6}$

$\boxed{V=\frac{1}{6}s^3}$

Thus the formula represents the volume of the pyramid is $\frac{s^3}{6}$

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3 years ago

I need help rlly bad I have no idea what’s the answer plsss help me!!!

valina [46]

So you can see the right angle is 90

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Classify the triangle by its angles and sides

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This is an Acute Isosceles Triangle. Hope this helps :)

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3 years ago

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2 years ago

Question 20 fast please

kipiarov [429]

Answer:

Square root of 4 is 2

so 1+ $\frac{[1+\sqrt{2x-1]}^2 }{4}$ =4

frac{[1+sqrt{2x-1]}^2 }{4}=3

so 1+sqrt{2x-1]}^2=12

so 1+sqrt{2x-1}=V12

sqrt{2x-1}=V12-1

2x-1=(V12-1)^2=12-2V12+1=13-2V12

2x=13+1-2V12

2x=14-2V12

x=7-V12

x=7-2V3

I put an attachment to explain better

Step-by-step explanation:

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2 years ago