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riadik2000 [5.3K]

3 years ago

10

Whick error did she do and what the correct answer

2 answers:

marusya05 [52]3 years ago

8 0

Answer:

The second one. The -2y should have been +2y

Step-by-step explanation:

a negative multiplied by a negative gives you a positive

leva [86]3 years ago

5 0

Answer:

it should be the second answer

Step-by-step explanation:

hope this helps

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At the North campus of a performing arts school 30% of students are music majors at the South campus 80% of the students are mus

OLEGan [10]

Answer:

It should be option B

Step-by-step explanation:

4 0

3 years ago

Find the solution of the given initial value problem. ty' + 6y = t2 − t + 1, y(1) = 1 6 , t > 0

gtnhenbr [62]

Answer:

Step-by-step explanation:

Given is a differential equation as

$ty' + 6y = t^2 - t + 1, y(1) = 1 6 , t > 0$

Divide this by t to get in linear form

$y'+6y/t = t-1+1/t$

This is of the form

y' +p(t) y = Q(t)

where p(t) = 1/t $e^(\int 1/tdt) = t$

So solution would be

$yt = \int t^2-t+1 dt\\= t^3/3-t^2/2+t+C$

siubstitute y(1) = 16

$16 = 16^3/3-128+1+C\\C = -1206$

4 0

3 years ago

6. which solid did the net form

In-s [12.5K]

Answer:

Hexagonal Pyramid

5 0

2 years ago

Find the slope of the line passing through the points (-6, 1) and (-7,5).

AlexFokin [52]

Answer:

y = -4x – 23

Hope this helps :)

4 0

2 years ago

Read 2 more answers

What is the solution set of x for the given equation? x^2/3=x^1/3+4=6 A. -2, -1 B. 2, -1 C. -8, -1 D. 8, -1 E. 2, 8

Valentin [98]

Answer:

Interpreting as: x^2/3=x^1/3+4=6 A

Input:

x^2/3 = x^(1/3) + 4 = 6 A

3 0

3 years ago