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yuradex [85]
3 years ago
9

Yolanda is saving money to buy a game. So far she has saved

Mathematics
2 answers:
LenaWriter [7]3 years ago
8 0
$25.

25/5=5
5x4=20

4/5 x 25 = 20
daser333 [38]3 years ago
6 0
The answer would be $25, trust me.

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Candice bought 3 shirts each shirt cost the same amount and was discounted by $3.66 Candice paid a total of $62.31 before tax. H
omeli [17]

Answer:

Step-by-step explanation:

Let the cost of each shirt be x.

Would assume each  shirt was discounted by 3.66

Amount to be paid for each :    x - 3.66

Total =    3*(x - 3.66)

3*(x - 3.66) = 62.31

x - 3.66 = 62.31/3

x - 3.66 =  20.77

x = 20.77 + 3.66

x = 24.43

Each shirt cost $24.43  before the discount.

3 0
3 years ago
What is the greatest number of right angles a hexagon can have?
finlep [7]
So hexagon is 6 sides and 6 angles
it can have a max of 2 right angles
if you make an irregular hexagon with one of the lines going into the figure then the answer is 4

if you have all the lines outside of the hexagon then the max is 2
 

a geoboard is a board with pegs that you can put rubber bands on to form  a figure.  google it

4 0
4 years ago
4)5 6)-15 please help
QveST [7]

Answer:

56-15=41is a required answer

6 0
3 years ago
A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

4 0
3 years ago
What is the value of the function y = 2x + 3 <br><br> x = -1
natita [175]
Y = 2x + 3
Y = 2(-1) + 3
Y = -2 + 3
Y = 1
4 0
3 years ago
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