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ss7ja [257]
3 years ago
9

The value of x in the equation 4^(2x+5)=8^(3x)

Mathematics
1 answer:
Roman55 [17]3 years ago
3 0
4⁽²ˣ ⁺ ⁵⁾ = 8³ˣ

But 4 = 2²  and 8 = 2³

4⁽²ˣ ⁺ ⁵⁾ = 8³ˣ

2²⁽²ˣ ⁺ ⁵⁾ = (2³)³ˣ

Multiply out the powers, also since the
 
 2⁴ˣ ⁺ ¹⁰ = 2⁹ˣ

Since the bases are the same, hence the powers are also the same.

4x + 10 = 9x

4x - 9x = -10

-5x = -10

x = -10/-5

x = 2

Hope this explains it.
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Step-by-step explanation:

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According to data from a medical​ association, the rate of change in the number of hospital outpatient​ visits, in​ millions, in
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Answer:

a) f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient​ visits, in​ millions, is given by:

f'(t)=0.001155t(t-1980)^{0.5}

a) To find the function f(t) you integrate f(t):

\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt

To solve the integral you use:

\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}

Next, you replace in the integral:

\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient​ visits.

Hence C' = 264,034,000

The function is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

3 0
3 years ago
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