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lakkis [162]
3 years ago
8

When additional independent variables are added to a simple linear regression, the coefficient of determination, R2 may ________

__.
A. increase or stay the same
B. become negative
C. decrease or stay the same
D. stay the same
Mathematics
1 answer:
lawyer [7]3 years ago
8 0

Answer:

Option A) increase or stay the same

Step-by-step explanation:

Coefficient of Determination:

  • It is interpreted as the proportion of the variance in the dependent variable that is predictable from the independent variable.
  • The coefficient of determination is the square of the correlation between predicted y scores and actual y scores.
  • If coefficient of determination is 0 means that the dependent variable cannot be predicted from the independent variable.
  • If coefficient of determination is 1 means the dependent variable can be predicted without error from the independent variable.
  • One problem with the coefficient of determination is that it always increases whenever we add a new independent variable

Thus, option A) is the correct answer.

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How many thousands = 4,000 ones
givi [52]
That would be 4 thousands
6 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
Mashcka [7]

Answer:

Part 1) -17\frac{8}{9} -----> -6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}

Part 2) -15.11 ------> -12.48-(-2.99)-5.62

Part 3) -19\frac{8}{9} -----> -19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})

Part 4) -201.65 -----> -353.92-(-283.56)-131.29

Part 5) 74 ------> 83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})

Step-by-step explanation:

Part 1) we have

-6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}

To calculate the subtraction convert the mixed numbers to an improper fractions

6\frac{4}{9}=\frac{6*9+4}{9}=\frac{58}{9}

3\frac{2}{9}=\frac{3*9+2}{9}=\frac{29}{9}

8\frac{2}{9}=\frac{8*9+2}{9}=\frac{74}{9}

substitute

-\frac{58}{9}-\frac{29}{9}-\frac{74}{9}=-\frac{(58+29+74)}{9}=-\frac{161}{9}

Convert to mixed number

-\frac{161}{9}=-(\frac{153}{9}+\frac{8}{9})=-17\frac{8}{9}

Part 2) we have

-12.48-(-2.99)-5.62

To calculate the subtraction eliminate the parenthesis first

-12.48-(-2.99)-5.62=-12.48+2.99-5.62=-15.11

Part 3) we have

-19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})

To calculate the subtraction convert the mixed numbers to an improper fractions

19\frac{2}{9}=\frac{19*9+2}{9}=\frac{173}{9}

4\frac{1}{9}=\frac{4*9+1}{9}=\frac{37}{9}

3\frac{4}{9}=\frac{3*9+4}{9}=\frac{31}{9}

substitute

-\frac{173}{9}-\frac{37}{9}-(-\frac{31}{9})

Eliminate the parenthesis

-\frac{173}{9}-\frac{37}{9}+\frac{31}{9}=\frac{(-173-37+31)}{9}=-\frac{179}{9}

Convert to mixed number

-\frac{179}{9}=-(\frac{171}{9}+\frac{8}{9})=-19\frac{8}{9}

Part 4) we have

-353.92-(-283.56)-131.29

To calculate the subtraction eliminate the parenthesis first

-353.92+283.56-131.29=-201.65

Part 5) we have

83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})

To calculate the subtraction convert the mixed numbers to an improper fractions

83\frac{1}{5}=\frac{83*5+1}{5}=\frac{416}{5}

108\frac{2}{5}=\frac{108*5+2}{5}=\frac{542}{5}

99\frac{1}{5}=\frac{99*5+1}{5}=\frac{496}{5}

substitute

\frac{416}{5}-\frac{542}{5}-(-\frac{496}{5})

Eliminate the parenthesis

\frac{416}{5}-\frac{542}{5}+\frac{496}{5}=\frac{(416-542+496)}{5}=\frac{370}{5}=74

3 0
3 years ago
Yes I know it’s to much but pleaseee...it’s due at 11 :(
Maurinko [17]
Same I don’t know , you can go online and pay someone to do it for you

8 0
3 years ago
In a chemical compound there are three parts zinc for every 16 parts copper by mass. A piece of the compound contains 320 g of c
Orlov [11]
<span>Total mass contains 320g copper. How many parts of 16g copper are there of the total mass of 320g copper? 320/16 = 20. There are 20 portions of 16g copper. (320/16) * 3 = 60g There are 60g of zinc in the compound.</span>
6 0
4 years ago
Can someone help . 8th grade math.
SVETLANKA909090 [29]

the answer should be if i did my math right is 0.25


8 0
4 years ago
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