Answer:
Horizontal distance = 1.98 m (Approx)
Step-by-step explanation:
Given:
Height = 2.5 m
Speed v = 2.8 m/s
Find:
Horizontal displacement
Computation:
s = ut + (1/2)gt²
2.5 = (1/2)(9.8)t²
t² = 0.5102
t = 0.7079 s
Horizontal distance = (v)(t)
Horizontal distance = (2.8)(0.7079)
Horizontal distance = 1.98 m (Approx)
Answer:
x_>0_>3000
Step-by-step explanation:
I saw the answer key :)
Answer:
<em>The answer is Hence Proved</em>
Step-by-step explanation:
Given that CB║ED , CB ≅ ED
To prove Δ CBF ≅ Δ EDF
This means that the length of CB is equal to ED
As CB║ED The following conditions satisfies when a transversal cut
two parallel lines
- ∠ EDF = ∠ FBC ( Alternate interior points )
- ∠ DEF = ∠ FCB ( Alternate interior points )
∴ Δ CBF ≅ Δ EDF ( By ASA criterion)
The Δ CBF is congruent to Δ EDF By ASA criterion .
<em> Hence proved </em>
Step-by-step explanation:
1. 5,11,17,23,29,35
Common difference is 6
3. 8,21,34, 47,60
Common difference is 13
5. 5,10,15,20,25
Common difference is 5
