Answer:
48
Step-by-step explanation:
1200/25=48
The area of the central rectangle = 5 * 3 = 15 ins^2
area of each triangle = 1/2*3*3 = 4.6 ins^2
Total area = 2*4.5 + 15 = 24 ins^2 (answer)
Answer:
The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.
Step-by-step explanation:
We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.
Let
= <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>
The z-score probability distribution for the sample mean is given by;
Z =
~ N(0,1)
where,
= population mean length of rods = 259.2 cm
= standard deviaton = 2.1 cm
n = sample of steel rods = 17
Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P(
> 259 cm)
P(
> 259 cm) = P(
>
) = P(Z > -0.39) = P(Z < 0.39)
= <u>0.65173</u>
The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.
Answer:
s = 7t
Step-by-step explanation:
Answer:
The percentage decrease = 0.9%
Step-by-step explanation:
Using the formula
Percentage Decrease = [ (Initial Value - Final Value) / |Initial Value| ] × 100
= [(9.80 - 9.71 ) / (9.80)] × 100
= [0.09 / 9.80] × 100
= 0.009 × 100
= 0.9%
Therefore, the percentage decrease = 0.9%