Question

A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the ball after 6.0 seconds? A. –9.6 meters/second B. 9.6 meters/second C. –19 meters/second D. 19 meters/second

Answer 1

Answer:

D. 19 m/sec to the nearest whole number.

Explanation:

v = u + at   where u = initial  velocity, v = final velocity a = acceleration and t = time.

v = 0 + 3.2 * 6

= 19.2.