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3 years ago

75 POINTS!!!

Chemistry

2 answers:

kap26 [50]3 years ago

6 0

Answer:

here

https://www.sciencea-z.com/science/resource/SL_Gr_3_Effects_of_Forces_L4_all_printable_resources.pdf

hope that helps

Nikolay [14]3 years ago

6 0

Answer:

i dont know

Explanation:

help me god

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Answer:

its D Her speed is 4.4 m/s, and her velocity is 4.4 m/s.

Explanation:

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4 years ago

Organic compounds ALL contain the element carbon. Which organic compound, used for stored chemical energy, contains carbon, hydr

Y_Kistochka [10]

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4 years ago

A student mixes in a test tube 3.00mL of 0.050M CuSO4with 7.00mL of 0.20M NH3/NH41 . The solution becomes a deep blue color. Ass

valkas [14]

Answer:

$\large \boxed{\text{0.0035 mol/L}}$

Explanation:

We are given the volumes and concentrations of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

Cu²⁺ + 4NH₃ ⟶ Cu(NH₃)₄²⁺

V/mL: 3.00 7.00

c/mol·L⁻¹: 0.050 0.20

1. Identify the limiting reactant

(a) Calculate the moles of each reactant

$\text{Moles of Cu}^{2+}= \text{3.00 mL solution} \times \dfrac{\text{0.050 mmol Cu}^{2+}}{\text{1 mL solution}} = \text{0.150 mmol Cu}^{2+}\\\\\text{Moles of NH}_{3} = \text{7.00 mL solution} \times \dfrac{\text{0.20 mmol NH}_{3}}{\text{1 mL solution}} = \text{0.140 mmol NH}_{3}$

(b) Calculate the moles of Cu(NH₃)₄²⁺ that can be formed from each reactant

(i) From Cu²⁺

$\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.150 mmol Cu}^{2+} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{1 mmol Cu}^{2+}}\\\\= \text{0.150 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}$

(ii) From NH₃

$\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.140 mmol NH}_{3} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{4 mmol NH}_{3}}\\\\= \text{0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}$

NH₃ is the limiting reactant, because it forms fewer moles of the complex ion.

(c) Concentration of the complex ion

$\text{The reaction forms 0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$ in a total volume of 10.00 mL.}\\c = \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{0.0350 mmol}}{\text{10.00 mL}} = \textbf{0.0035 mol/L}\\\\\text{The concentration of the complex ion is $\large \boxed{\textbf{0.0035 mol/L}}$}$

7 0

3 years ago

Suppose you will determine the composition of the unknown substance that was collected at the scene of the crime. You are encour

maria [59]

Answer:

b erergart

Explanation:

6 0

3 years ago

You have two containers at 0°C and 1 atm. One has 22.4 L of hydrogen gas, and the other has 22.4 L of oxygen gas.

valentinak56 [21]

Answer:

Explanation:

According to Avogadro's law, equal volumes of different gases at the same temperature and pressure have equal number of molecules.

It cannot however be a because according to ideal gas equation the number of moles in each container is 0.999moles which translates to 6.019*10^23 molecules

4 0

3 years ago