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3 years ago

75 POINTS!!!

Chemistry

2 answers:

kap26 [50]3 years ago

6 0

Answer:

here

https://www.sciencea-z.com/science/resource/SL_Gr_3_Effects_of_Forces_L4_all_printable_resources.pdf

hope that helps

Nikolay [14]3 years ago

6 0

Answer:

i dont know

Explanation:

help me god

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Pb(OH)Cl, one of the lead compounds used in ancient Egyptian cosmetics, was prepared from PbO according to the following recipe:

sladkih [1.3K]

Answer:

8.59 g

2.25 g

Explanation:

According to the given situation the calculation of grams of PbO and grams of NaCL is shown below:-

Moles of Pb(OH)CL is

$= \frac{Mass}{Molar\ mass}$

$= \frac{10.0 g}{259.65g / mol}$

= 0.0385 mol

Mass of PbO needed is

$= 0.385mol Pb(OH) Cl\times \frac{1 mol PbO}{1molpb (OH) cl} \times \frac{223.2g PbO}{1mol PbO}$

After solving the above equation we will get

= 8.59 g

Mass of NaCL needed is

$= \frac{1mol\ NaCl}{1molPb\ (OH)Cl} \times \frac{58.45NaCl}{1mol NaCl}$

After solving the above equation we will get

= 2.25 g

Therefore we have applied the above formula.

7 0

3 years ago

How many sulfur atoms are in 0.45 mol BaSO4??

Lemur [1.5K]

$(0.45 mol BaSO_{4})*(\frac{6.022*10^23 molecules}{mol})*(\frac{1 atom S}{1 molecule BaSO_{4}}) = 2.7*10^{23}$

4 0

3 years ago

Read 2 more answers

Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o

vivado [14]

Answer:

For 1: The amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

For 2: The amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

Explanation:

For 1:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

Molarity of $KIO_3$ solution = 0.0100 M

Volume of solution = 25 mL

Putting values in above equation, we get:

$0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol$

Hence, the amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

For 2:

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

$2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3$

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.00025 moles of potassium iodate will react with = $\frac{1}{2}\times 0.00025=0.000125mol$ of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

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3 years ago

Flammable materials, like alcohol, should never be

jarptica [38.1K]

Answer:

b.open flame because it is fundamental end of the alcohol mixes in with the flame then it will become a bigger fire

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3 years ago

______ have no definite shape, but definite volume

NemiM [27]

Answer:

liquids

Explaination:

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3 years ago