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Svetllana [295]
3 years ago
10

13 moles of water to molecules

Chemistry
1 answer:
FromTheMoon [43]3 years ago
6 0
I’m confused what are you asking exactly?
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A water sample is found to contain 59 ppm
NeX [460]

Explanation:

k so basically u gotta do 59/1000000 then multiply that by 972 which gives u 0.057348

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3 years ago
What characteristic of rivers at their source gives them so much power to shape the land
Zielflug [23.3K]
River sources tend to be at the top of mountains or areas of high elevation. This means that rivers impact the entire terrain from mountains to seas and oceans.

I hope this Helps!
8 0
3 years ago
Which is less likely to be a relatable source of information the webpage of a university or the webpage a scientist who is tryin
faltersainse [42]

Answer:

The web page of a university

Explanation:

A scientist can be more biased within coming to information about pretty much anything. I have had multiple science teachers who seem more biased on to something else and pretend that they're right just cause they know what they are doing.

Then the university would be a great choice because its controlled by a higher state, then also the consistency of being updated.

7 0
3 years ago
It takes 495.0 kJ of energy to remove 1 mole of electron from an atom on the surface of sodium metal. How much energy does it ta
Zigmanuir [339]

Answer:

\lambda=241.9\ nm

Explanation:

The work function of the sodium= 495.0 kJ/mol

It means that  

1 mole of electrons can be removed by applying of 495.0 kJ of energy.

Also,  

1 mole = 6.023\times 10^{23}\ electrons

So,  

6.023\times 10^{23} electrons can be removed by applying of 495.0 kJ of energy.

1 electron can be removed by applying of \frac {495.0}{6.023\times 10^{23}}\ kJ of energy.

Energy required = 82.18\times 10^{-23}\ kJ

Also,  

1 kJ = 1000 J

So,  

Energy required = 82.18\times 10^{-20}\ J

Also, E=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

So,  

79.78\times 10^{-20}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{82.18\times 10^{-20}}

\lambda=\frac{10^{-26}\times \:19.878}{10^{-20}\times \:82.18}

\lambda=\frac{19.878}{10^6\times \:82.18}

\lambda=2.4188\times 10^{-7}\ m

Also,  

1 m = 10⁻⁹ nm

So,  

\lambda=241.9\ nm

6 0
3 years ago
Brj fceq wej plz come everyone <br><br>only girl​
Fittoniya [83]

Explanation:

what is this guy's

tellllll me clearly

5 0
2 years ago
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