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Art [367]
3 years ago
6

True or false? A circle could be circumscribed about the quadrilateral below.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0

A circle can be circumscribed about a quadrilateral if and only if the opposite angles of the quadrilater sum up to 180.

This is not the case, so you can't circumscribe a circle about the quadrilateral.

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Please answer this quickly 23 x 18
topjm [15]
Answer: 414

Explanation:
8 0
2 years ago
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Perform the following division. Round the answer to three decimal places. Use paper and pencil to calculate the problem. 0.64 ÷
kumpel [21]

Answer:

0.168

Step-by-step explanation:

0.64 ÷ 3.8

To divide this number first we need to remove the decimal point from the given problem 3.8

In 0.64 ,We have 64 after the decimal point so we multiply by 100

We multiply both numbers by 10

0.64* 100 is 64

3.8 * 100 is 380

Now we do 64 ÷ 38 0

We put 64 inside and 380 outside. We use long division

When we put decimal point at the top then we add 0 with 64

                              0 . 1 6 8 4

                      ---------------------------------------              

           380              640

                                 380

                     ------------------------------------------(subtract)

                                 260 0

                                 2280

                 -------------------------------------------(subtract)

                                   320 0

                                    3040

                          --------------------------------(subtract)

                                     160 0

                                      1520

                        ----------------------------------(subtract)

                                       80  and it goes on

      quotient is 0.1684

When we round to three decimal places it becomes 0.168      

4 0
3 years ago
darlene wants to buy martian invader video game. The video game price is $100. Darlene has a coupon for 25%. What is the price o
Paraphin [41]

Answer:

$75

Step-by-step explanation:

100 ÷ 25=75

Hope this helps!☺

6 0
3 years ago
What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0
Tom [10]

Answer:

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

Step-by-step explanation:

The given equation is

(2x+3)^2+8(2x+3)+11=0

Let us treat this as a quadratic equation in (2x+3).

where a=1,b=8,c=11

The solution is given by the quadratic formula;

(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}

We substitute these values into the formula to obtain;

(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}

(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}

(2x+3)=\frac{-8\pm \sqrt{20} }{2}

(2x+3)=\frac{-8\pm2\sqrt{5} }{2}

(2x+3)=-4\pm \sqrt{5}

(2x+3)=-4-\sqrt{5} or (2x+3)=-4+ \sqrt{5}

2x=-3-4-\sqrt{5} or 2x=-3-4+ \sqrt{5}

2x=-7-\sqrt{5} or 2x=-7+ \sqrt{5}

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

5 0
3 years ago
Pls heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeelp
VashaNatasha [74]
1.1

Hope this helps:)
3 0
3 years ago
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