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Art [367]
3 years ago
6

True or false? A circle could be circumscribed about the quadrilateral below.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0

A circle can be circumscribed about a quadrilateral if and only if the opposite angles of the quadrilater sum up to 180.

This is not the case, so you can't circumscribe a circle about the quadrilateral.

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Can someone help me with problems J-L PLZZZ ITS URGENT DUE TOMORROW AND I REALLY NEED HELP AND IM SO TIRED
siniylev [52]

h. y / x^2

j. 0.00001

k. 0.000005

I. 0.025

m. 8 times 10^-3

n. 1.25 times 10^-4

o. 5 times 10^-7

p. 0.000000001

I only did the ones I see, hope it helps.

3 0
3 years ago
A triangle has side lengths of (x-6), (x+2) and (x-9). Find the perimeter of the triangle
Setler [38]

Answer:

3x - 13

Step-by-step explanation:

The perimeter is just the distance around the triangle. We have all three sides, so we can just add them together to get the total distance.

(x-6) + (x+2) + (x-9)

Group:

x + x + x - 6 + 2 - 9

3x - 13

8 0
3 years ago
Hiroto paid $4.28 in sales tax for the items that he purchased.
Katena32 [7]

Answer:

  $68.48

Step-by-step explanation:

You want to find cost such that ...

  6.25% × cost = $4.28

Dividing by the coefficient of cost, we get ...

  cost = $4.28/0.0625 = $68.48

8 0
3 years ago
What are the roots of the equation? x^2+24=14×
defon
\begin{gathered} x^2+24=14x \\ x^2-14x+24=0 \end{gathered}

Therefore,

\begin{gathered} x^2-14x+24=0 \\ x^2-2x-12x+24=0 \\ x(x-2)-12(x-2)=0 \\ (x-2)(x-12)=0 \\ x=2 \\ or\text{ } \\ x=12 \end{gathered}

6 0
1 year ago
Write a quadratic relation in the form y = ax2 + bx + c with roots 4 and - 3 and
pochemuha

Answer:

y =  2*x^2 - 2*x - 24

Step-by-step explanation:

If we have a quadratic function with roots a and b, we can write the equation for that function as:

y = f(x) = A*(x - a)*(x - b)

Where A is the leading coefficient.

In this case, we know that the roots are: 4 and -3

Then the function will be something like:

f(x) = A*(x - 4)*(x - (-3) )

f(x) = A*(x - 4)*(x + 3)

Now we need to determine the value of A.

We also know that the graph of the function passes through the point (3, -12)

This means that:

f(3) = -12

Then:

-12 = A*(3 - 4)*(3 + 3)

-12 = A*(-1)*(6)

-12 = A*(-6)

-12/-6 = A

2 = A

Then the equation is:

y = f(x) = 2*(x - 4)*(x + 3)

Now we need to write this in standard form, so we just need to expand the equation:

y = f(x) = 2*(x^2 + x*3 - x*4 - 4*3)

y = f(x) = 2*(x^2 - x - 12)

y = f(x) = 2*x^2 - 2*x - 24

Then the relation is:

y =  2*x^2 - 2*x - 24

4 0
3 years ago
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