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Art [367]
3 years ago
6

True or false? A circle could be circumscribed about the quadrilateral below.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0

A circle can be circumscribed about a quadrilateral if and only if the opposite angles of the quadrilater sum up to 180.

This is not the case, so you can't circumscribe a circle about the quadrilateral.

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Me ajudem com a 3º questão
Alisiya [41]

I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.

10 = \dfrac{n(n-3)}{2}

20 = n^2 - 3n

n^2 - 3n - 20 = 0

Answer: n² - 3n - 20 = 0

That doesn't factor so there is no integer n solution.

That means there are no polygons with 10 diagonals.

n = \frac 1 2(3 \pm \sqrt{89})

7 0
3 years ago
Write -3i + (3/4+2i) - (9/3+3i) as a complex number in standard form
bogdanovich [222]

Answer:

=  -3i + (3/4+2i) - (9/3+3i)

= (3/4 - 9/3) + (-3 + 2 -3)i

= -9/4 -4i

4 0
3 years ago
Plz solve . 3+ x > -9
STALIN [3.7K]

Answer:

12

Step-by-step explanation:

3 + x>-9 x=12 15>-9

5 0
3 years ago
Can you figure out the formula
puteri [66]

If "a" and "b" are two values of x-coordinate, and "m" is the midpoint between them, it means the distance from one end to the midpoint is the same as the distance from the midpoint to the other end

... a-m = m-b

When we add m+b to this equation, we get

... a+b = 2m

Solving for m gives

... m = (a+b)/2

This applies to y-coordinates as well. So ...

... The midpoint between (x1, y1) and (x2, y2) is ((x1+x2)/2, (y1+y2)/2)

_____

Jennifer had (x1, y1) = (-4, 10) and (x2, y2) = (-2, 6). So her calculation would be

... midpoint = ((-4-2)/2, (10+6)/2) = (-6/2, 16/2) = (-3, 8)

Brandon had (x1, y1) = (9, -4) and (x2, y2) = (-12, 8). So his calculation would be

... midpoint = ((9-12)/2, (-4+8)/2) = (-3/2, 4/2) = (-1.5, 2)

4 0
3 years ago
Evaluate
Fittoniya [83]
Answer: 8

Explanation: first start with the fractions. 4 divided by a (which equals 4) is 1. B (which equals 3) divided by 3 is 1. Then put it all together 6+1+1=8.
6 0
3 years ago
Read 2 more answers
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