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2 years ago

Solve variable 3/4x-5=7

Mathematics

1 answer:

soldi70 [24.7K]2 years ago

5 0

Answer:

x=16

Step-by-step explanation:

7+5=12

12 divided by 3/4 is 16

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(-5,-1); 2y=2x-4 help me ASAP please

PIT_PIT [208]

Answer:

u trrahs at fritnote

Step-by-step explanation:

6 0

2 years ago

What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*

pickupchik [31]

<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation $x^4-41x^2=-400$ .

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

$x^4-41x^2+400=-400+400$ .

$x^4-41x^2+400=0$ .

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

$x^4-25x^2-16x^2+400=0$

Making it into two groups, we get

$(x^4-25x^2)+(-16x^2+400)=0$

Factoring out GCF of each group, we get

$x^2(x^2-25)-16(x^2-25)=0$

$(x^2-25)(x^2-16) =0$

Factoring out $(x^2-25)$ and $(x^2-16)$ separately by difference of the squares identity $a^2-b^2=(a-b)(a+b)$ , we get

$(x^2-25) = x^2-5^2= (x-5)(x+5)$ and

$x^2-16 = x^2-4^2 =(x-4)(x+4)$ .

Therefore,

$(x-5)(x+5)(x-4)(x+4) =0$

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

6 0

2 years ago

Yesterday, stanley's doughnut shop sold 2/3 as many chocolate doughnuts as cinnamon doughnuts. if they sold 7 1/4 trays of cinna

katovenus [111]

You figure out the amount of chocolate doughnuts sold by multiplying 2/3 by 7 1/4

first you change 7 1/4 to an improper fraction:
7 1/4= 29/4
now multiply 2/3×29/4 by multiplying the two numerators then putting that over the two denominators multiplied: (2×29)/(3×4)=58/12
now simplify:58/12=4 10/12= 4 5/6

the answer is Stanley's doughnut shop sold
4 5/6 trays of chocolate doughnuts

5 0

2 years ago

( PLEASE HELP) The points (3,-2) (-3,-2) and (-3,6) are the vertices of a triangle. Find the perimeter of the triangle. (Hint: U

True [87]