Answer:
Altitude of cylinder = 10 cm
Step-by-step explanation:
Given:
lateral surface area of cylinder = 90 cm²
Circumference of base = 9 cm
Find:
Altitude of cylinder
Computation:
Circumference of base = Circumference of cylinder
So,
2πr = 9
lateral surface area of cylinder = 2πrh
2πrh = 90
We know that; 2πr = 9
So,
9(h) = 90
h = 90 / 9
Altitude of cylinder = 10 cm
Answer:
C. ⅐
Step-by-step explanation:
Recall: the slope of a line that is perpendicular to another is the negative reciprocal of the slope of the other line that it is perpendicular to.
Thus:
Slope of red line = -7
The green line that is perpendicular to the red line will have a slope that is the negative reciprocal of -7.
Negative reciprocal of -7 = ⅐
The slope of the green line is therefore ⅐
Answer:
= 8 - 11n
Step-by-step explanation:
These are the terms of an arithmetic sequence with n th term
= a + (n - 1)d
where a is the first term and d the common difference
here a = - 3 and
d = - 14 - (- 3) = - 14 + 3 = -11, thus
= - 3 - 11(n - 1)
= - 3 - 11n + 11
= 8 - 11n
Answer: Orange = 5 rupee
Apple = 6 rupees
Step-by-step explanation:
Let the cost of an orange be x
Let the cost of an apple be y
We can form an equation from the question given which will be:
5x + 3y = 43 ......... i
2x + 4y = 34 ......... ii
Multiply equation i by 2
Multiply equation ii by 5
10x + 6y = 86 ........ iii
10x + 20y = 170 ..... iv
Subtract iii from iv
14y = 84
y = 84/14
y = 6
An apple cost 6 rupees
Since from equation ii
2x + 4y = 34
2x + 4(6) = 34
2x + 24 = 34
2x = 34 - 24
2x = 10
x = 10/2
x = 5
An orange cost 5 rupee
-π/2 < arctan(x) < π/2
So cos(π/2) < cos(arctan(x)) < cos(0)
0 < cos(arctan(x)) < 1
