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2 years ago

11

Suppose the number of eggs used in Exercise 4 is changed to 3 eggs for each batch of 12 muffins, and 48 eggs are used. How many

batches and how many muffins will be made?

1 answer:

wel2 years ago

5 0

3 eggs for 12 muffins
6 eggs for 24 muffins
9 eggs for 36 muffins
30 eggs for 120 muffins

48 eggs for 192 muffins = 16 batches

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Lana has $15 for dinner her meal is $13.90 she wants to leave a 18% tip does she have enough explain your answer

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Start off by finding 18% of 13.90.

18%=18/100=0.18

0.18(13.9)=2.5

An 18% tip would be $2.50.

Now, to find out if Lana has enough money, add $2.50 to $13.90 to find out the total amount she would leave. You get $16.40. Since $16.40>$15, the answer is no because the total cost including the 18% tip is greater than $15.

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3 years ago

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Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th

Digiron [165]

Answer:

$P(X = 0) = 0.0263$

$P(X = 1) = 0.1407$

$P(X = 2) = 0.3012$

$P(X = 3) = 0.3224$

$P(X = 4) = 0.1725$

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Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 5, p = 0.517$

Distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263$

$P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407$

$P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012$

$P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224$

$P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725$

$P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369$

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Step-by-step explanation:

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