Answer:
7/16.
Step-by-step explanation:
The first triangle has no shading.
The second triangle has 1/4 shaded.
The third has 3/9.
The fourth has 6/16.
Based on this pattern, we can assume that the number of small triangles in each triangle are going to be squared of numbers, since the first had 1, the second 4, the third 9, the fourth 16. So, the 8th triangle would have 8^2 small triangles, or 64 triangles in total.
The first triangle has no shaded triangles. The second has 1. The third has 3. The fourth has 6. If you study the pattern, the second triangle has 1 more than the previous, the third has 2 more, the fourth has three more. And so, the fifth triangle would have 6 + 4 = 10 triangles, the sixth would have 10 + 5 = 15 triangles, the seventh would have 15 + 6 = 21 triangles, and the eighth would have 21 + 7 = 28 shaded triangles.
So, the fraction of shaded triangles would be 28 / 64 = 14 / 32 = 7 / 16.
Hope this helps!
Answer: The largest angle formed during his trip is at the mall between his home and the library.
Step-by-step explanation:
Hi, since the situation forms a right triangle (see image attached) the angle formed between his home and the library is 90°.
The sum of the interior angles of a right triangle is 180°, and the right angle (90°)is the largest angle formed.
So, the largest angle formed during his trip is at the mall between his home and the library.
Feel free to ask for more if needed or if you did not understand something.
Answer:
y =3
Step-by-step explanation:
Slope of zero means it is a horizontal line
Horizontal lines are of the form
y =
The y coordinate is 3 so
y =3
Answer:
8.5 * 10^-3
Step-by-step explanation:
In this case, to prove what is required, we must use the Pythagorean theorem to find the diagonal of the square.
If the diagonal of the square is smaller than the diameter of the circle, then the square will fit perfectly in the circle without touching it.
Diagonal = Root ((7 ^ 2) + (7 ^ 2)) = 9.89 cm.
we observed that
9.89cm <11cm.
Therefore we show that:
the square will fit inside the circle without touching the edge of the circle