Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
No
Step-by-step explanation:
Answer:
6 hours
Step-by-step explanation:
Answer:
6 hours
Step-by-step explanation:
Firstly, it is important to know where the train that leaves Washington will get after one hour since they didn't start at the same time between noon and 1 is 1 hour.
Speed = distance / time
Distance = speed * time
The distance S = 44 * 1
S= 44m
To determine the time they will pass each other
500(total distance)- 44 ( distance gotten to in 1 hour) - d(the distance it willl pass each other =44* t(time the train will pass each other.
456-d =44t
Second train
d = 32t
Substituting to the equation
456-32t=44t
456=76t
t= 6 hours.
The time they will pass each other is six hours.
