1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kryger [21]
3 years ago
6

Can someone please help me with this

Mathematics
1 answer:
marta [7]3 years ago
7 0
N=4.5 In the picture are the steps you should follow to solve for n.

You might be interested in
Which of the following functions best describes this graph?​
jok3333 [9.3K]
<h3>Answer: Choice C</h3>

Explanation:

The x intercepts or roots are x = 3 and x = 5, which lead to the factors x-3 and x-5 respectively.

Multiplying out those factors gets us this:

(x-3)(x-5)

x(x-5)-3(x-5)

x^2-5x-3x+15

x^2-8x+15

8 0
3 years ago
In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the
Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

(AB)^2=(BC)^2+(AC)^2

(13)^2=(BC)^2+(5)^2

169=(BC)^2+25

BC=12

\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}

\sin A=\frac{BC}{AB}

A=\sin ^{-1}\frac{12}{13}

A=67.38

Bisector divides the angle in two equal parts, therefore,

A'=\frac{67.38}{2} =33.69

In triangle ACD.

\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}

\cos A'=\frac{AC}{AD}

\cos (33.69^{\circ})=\frac{5}{AD}

0.832=\frac{5}{AD}

AD=\frac{5}{0.832} =6.009\approx 6.01

Therefore the length of the angle bisector of angle ∠A is 6.01.

4 0
3 years ago
Math question quadratics
denpristay [2]

Answer: The length and width are 50 and 30 meters (or 30 and 50 meters).

Step-by-step explanation:

To solve this question, we can represent variables for the length and width in two equations.

2l + 2w = 160\\\\l * w= 1500

To solve for one of the variables, you'll have to substitute one of the variables, so solve for one of them:

2l = 160 - 2w\\l = 80 - w

(80-w)*w=1500\\\\-w^2 + 80w - 1500 = 0\\\\w^2 - 80w + 1500 = 0

Now, we have a standard quadratic equation that we can factor. When factoring, you'll get this:

(w-50)(w-30) = 0

This tells us that the width could be either 50 or 30.

Substitute 50 into one of the equations to find the length:

2 (l) + 100 = 160

l = 30.

The length and width are 50 and 30 meters (or 30 and 50 meters).

4 0
3 years ago
Read 2 more answers
Please help asap oiuytyghjkjhugytfhjkl
Alika [10]

Answer:

112

Step-by-step explanation:

correct me if im wrong.

I got this from doing 30 percent out of 160

160×0.30

160-48=112

7 0
3 years ago
Read 2 more answers
Which of the following is equivalent to 4x+6=12? Please show work.
Natasha_Volkova [10]
4x+6=12
4x=12-6
4x=6
4x/4=6/4
X=1.5
4 0
3 years ago
Read 2 more answers
Other questions:
  • Is there an outlier in the data set? Explain your reasoning.
    7·2 answers
  • A painter charges $15.36 per hour, plus an additional amount for the supplies. If he made $187.93 on a job where he worked 7 hou
    9·1 answer
  • There were 475 seats set up for the school play at one performance 189 of the seats were empty how many seats were filled at tha
    5·2 answers
  • What two number multiplies to get 15 and adds to get 6
    8·1 answer
  • A pizza 16 inches in diameter is cut into 8 congruent slices. Find the area of the sector of one piece of pizza.
    9·1 answer
  • Are the following rational or irrational?
    6·1 answer
  • The area of a parallelogram is 12 ftsquared and the height is 4 ft. Find the length of the corresponding base.
    10·1 answer
  • There are 12 female students and 18 male students in a class. Which of the following expresses the ratio of female students to m
    14·1 answer
  • 6(2x-11)+15=21
    15·2 answers
  • Calculate the volume of a cylinder of radius 5cm and height 14cm (take pie 22/7)
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!