Responder:
39200 J
Explicación:
Dado:
Masa de Tamara (m) = 50 kg
Altura a la que se encuentra Tamara (h) = 80 m
Aceleración debido a la gravedad (g) = 9.8 m / s²
La energía potencial de un objeto de masa 'm' ubicada a una altura 'h' sobre el suelo se da como:
Ahora, conecte los valores dados y resuelva la energía potencial. Esto da,
Por lo tanto, la energía potencial de Tamara ubicada a una altura de 80 m es 39200 J.
Answer:
Velocity v= 12.25
Explanation:
The first rock dropped give the distance Y in meters
Now the motion of the second rock the time change so to know the velocity
To solve this problem we could apply the concepts given by the conservation of Energy.
During the launch given in terms of kinetic energy and reaching the maximum point of the object, the potential energy of the body is conserved. However, part of all this energy is lost due to the work done by the friction force due to friction with the air, therefore
The potential and kinetic energy are conserved and are the same PE = KE and this value is equivalent to 100J, therefore
The kinetic energy will ultimately be less than 100J, so the correct answer is C.
