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LiRa [457]
4 years ago
13

a football is kicked at an 50 degree angle to the horizontal , travels a horizontal distance of 20m before hitting the ground. w

hat is the initial speed?

Physics
1 answer:
zimovet [89]4 years ago
8 0
So initial velocity of football is 14.25 m/s

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I need help on this one please
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Lithium shares more properties with Sodium, because they have the same number of valence electrons (one). Choice 1 is correct. Hope this helps!

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3 years ago
What is the role of Langerhans cells?
boyakko [2]

     

Langerhans cells exist on the surface of the skin. They help to protect you by keeping dangerous microbes from entering your body. Langerhans cells do this in two very different ways: by protecting your skin from infection and also by stimulating allergic reactions.

 

4 0
3 years ago
A transverse wave has a frequency of 200 Hz with a wavelength of 1.0 m. Determine the speed
Lana71 [14]

Answer:

200 m\ s Ans .....

Explanation:

Data:

f = 200 Hz

w = 1.0 m

v = ?

Formula:

v = f w

Solution:

v = ( 200)(1.0)

v = 200 m\s <em>A</em><em>n</em><em>s</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

7 0
3 years ago
Two forces act on a 16 kg object. The first force has a magnitude of 68 N and is directed 24 degrees north of east. The second f
Vlada [557]

Answer:

The correct Answer to the question is : e) 4.1 m/s^2, 52 degrees north of east

Explanation:

F1= 68 N < 24º = 62.12 i + 27.65 j

F2= 32N < 132º = -21.41 i + 23.78 j

R= F1+F2= 40.71 i +51.43 j = 65.59 N < 51.63 º

By 2nd law of newton:

F= m * a

R= m*a

a= R/m

a= 4.1 m/s² < 52º  (52 degrees north of east)

I consideer 0º at the EAST axis.

4 0
3 years ago
Read 2 more answers
If an object falls and ends with a velocity of 58.8 m/s, how long was the<br><br> object falling?
tensa zangetsu [6.8K]

Answer:

the time taken for the object to fall is 6 s.

Explanation:

Given;

final velocity of the object, v = 58.8 m/s

initial velocity of the object, u = 0

The height of fall of the object is calculated as;

v² = u² + 2gh

v² = 2gh

h = \frac{v^2}{2g} \\\\h = \frac{(58.8)^2}{2(9.8)} \\\\h = 176.4 \ m

The time to fall through the height is calculated as;

h =ut+  \frac{1}{2} gt^2\\\\h = 0 +  \frac{1}{2} gt^2\\\\h =  \frac{1}{2} gt^2\\\\t= \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 176.4}{9.8} } \\\\t = 6 \ s

Therefore, the time taken for the object to fall is 6 s.

6 0
3 years ago
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