Ask question

Ask question

All categories

3 years ago

14

A hungry hawk was preying on a lizard who was running northwards to get away from the low-flying hawk. If the lizard can run 8m

across water in 4s, what is the lizard's velocity? (Speed: D/T)

1 answer:

Anastaziya [24]3 years ago

8 0

Answer:

2m/s²

Explanation:

velocity = displacement (distance in a specified direction /time

You might be interested in

A box of mass 20kg is pulled up an inclined plane by a force of 285N. Given that the value of the incline angle is 30 degrees an

docker41 [41]

Given :

Mass of box , m = 250 kg.

Force applied , F = 285 N.

The value of the incline angle is 30°.

the coefficient of dynamic friction is $\mu=0.72$ .

To Find :

The speed with which the box is moving with, assuming it takes 4 seconds to reach the top of the incline.

Solution :

Net force applied in box is :

$F=285 - mgsin\ \theta - \mu mg cos \ \theta\\ \\F=285-mg( sin \ \theta - \mu cos\ \theta)\\\\F=285 - 20\times 10( \dfrac{1}{2}+0.72\times \dfrac{\sqrt{3}}{2})\\\\F=60.29\ N$

Acceleration , $a=\dfrac{F}{m}=\dfrac{60.29}{20}=3.01\ m/s^2$ .

By equation of motion :

$v=u+at\\\\v=0+3.01\times 4\\\\v=12.04\ m/s$

Therefore, the speed of box is 12.04 m/s.

Hence, this is the required solution.

6 0

3 years ago

If an element has 7 electrons how many of them will be in the 2nd energy level

inna [77]

Well first you can not go to the 2nd energy level without the first so the first takes up 2 electrons leaving you 5 electrons and the recommended amount is 8 electrons so you would have 5 electrons left

8 0

4 years ago

Read 2 more answers

Before 2006, while Pluto was still considered a planet, people used this saying to remember the nine planet names: "My very exce

Serjik [45]

Answer:

Mother's Visit Evoked My Junior Sister's Unseen Niceness

Explanation:

Mother's - M - stands for Mercury

Visit - V - Stands for Venus

Evoked - E - Stands for Earth

My - M - stands for Mars

Junior -J - stands for Jupiter

Sister's -S- Stands for Saturn

Unseen -U - stands for Uranus

Niceness - S- stands for Neptune

4 0

3 years ago

What explains the dramatically different magnitudes of accelerations that result when a mosquito collides head on with a moving

Evgen [1.6K]

Answer:

Mass of the vehicle and small bug.

Explanation:

By Newton's third law, force on bug and vehicle will be same when they collide with each other irrespective of their masses.

But according to Newton's second law, force is mass times acceleration. Since the force on each mass is same, the smaller mass will accelerate more and the heavier mass will accelerate less for the same force.
Therefore the acceleration of bug will be very greater than vehicle as the mass of the bug is very small as compared to vehicle.

Learn more about Newton's law.

brainly.com/question/974124

#SPJ10

7 0

2 years ago

Consider two soap bubbles with radius r1 and r2 (r1 <r2) connected via a valve. What happens if we open the valve

Sedaia [141]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The pressure difference of the first bubble is $\Delta P _1 =10 J/m^3$

The pressure difference of the second bubble is $\Delta P _2 =20 J/m^3$

The pressure difference on the second bubble is higher than that of the first bubble so when the valve is opened pressure from second bubble will cause air to flow toward the first bubble making is bigger

Explanation:

From the question we are told that

The radius of the first bubble is $r_1 = 10 \ mm=0.01 \ m$

The radius of the second bubble is $r_2 = 5 \ mm = 0.005 \ m$

The surface tension of the soap solution is $s = 25 \ mJ/m^2 = 25*10^{-3} J/m^2$

Generally according to the Laplace's Law for a spherical membrane the pressure difference is mathematically represented as

$\Delta P = \frac{4 s}{R}$

Now the pressure difference for the first bubble is mathematically evaluated as

$\Delta P _1 = \frac{4 s}{r_1}$

substituting values

$\Delta P _1 = \frac{4 *25 *10^{-3}}{0.01}$

$\Delta P _1 =10 J/m^3$

Now the pressure difference for the second bubble is mathematically evaluated as

$\Delta P _2 = \frac{4 s}{r_1}$

$\Delta P _2 = \frac{4 *25 *10^{-3}}{0.005}$

$\Delta P _2 =20 J/m^3$

3 0

3 years ago