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SCORPION-xisa [38]

4 years ago

6

When blue light of wavelength 470 falls on a single slit, the first dark bands on either side of center are separated by 45.0. d

etermine the width of the slit

1 answer:

enyata [817]4 years ago

3 0

For Fraunhofer diffraction at a single slit would be represented by:

<span>a sinθ = mλ

</span><span>It should be noted that the angle needs be halved because we are only concerned with the angle between m=1 and m=0 and they gave you the angle between m=1 to the right of the center and m=1 on the left of the center. We calculate as follows:
</span>
<span>a sin(45/2)=(1)(470)
a = 1228 nm

Hope this answers the question. Have a nice day.
</span>

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a car takes off from rest and covers a distance of 80m on a straight road in 10s.calculate the magnitude of its acceleration

olasank [31]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Here's the solution :

Let's find the final velocity :

$\dfrac{displacement}{time}$

$\dfrac{80}{10}$

$8 \: \: ms {}^{ - 1}$

Initial velocity (u) = 0 (cuz it started from rest)

Final velocity (v) = 8 m/s

Time taken (t) = 10 sec

now, we know that :

$acceleration = \dfrac{v - u}{t}$

$\dfrac{8 - 0}{10}$

$\dfrac{8}{10}$

$0.8 \: \: m {s}^{ - 2}$

Acceleration = 0.8 m/s²

7 0

3 years ago

A single conservative force F(x) = b x + a acts on a 4.37 kg particle, where x is in meters, b = 6.09 N/m and a = 5.96 N. As the

Alenkasestr [34]

Answer:104.41 J

Explanation:

Given

Force acting $F(x)=bx+a$

mass of particle $m=4.37 kg$

$a=5.96 N$

$b=6.09 N/m$

Work done is given by

$W=\int_{a}^{b}F.dx$

$W=\int_{0.652}^{5.1}\left ( 6.09x+5.96\right )dx$

$W=\left [ 6.09\times \left ( \frac{x^2}{2}\right )+5.96\times x\right ]_{0.652}^{5.1}$

$W=77.906+26.51 J$

$W=104.41 J$

4 0

4 years ago

If a bit is travelling through a copper wire at 2 x 10 8 meters per second, how far does it go in a millisecond?

zavuch27 [327]

Answer:

$2\times10^5$ m

Explanation:

1 second = 1000 millisecond, so if within 1 second a bit could travel a distance of $2\times10^8$ m through a copper wire then within a millisecond (a thousandth of a second) it should be able to travel through a distance of

$\frac{2\times10^8}{1000} = 2\times10^5$ m

3 0

4 years ago

Newtons first law of motion describes

Tems11 [23]

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

3 0

3 years ago

Suppose a truck has a momentum of 40,120 kg • and a mass of 1,180 kg. What is the truck’s velocity?

gladu [14]

<u>Answer:</u>

The velocity of the truck is 34 m/s.

<u>Explanation:</u>

The momentum (p) of an object is the product of its mass (m) and its velocity (v) which can be written as:

<em>p = mv</em>

Here in this problem, we are given a truck which has a momentum of 40120 kg and a mass of 1180 kg and we are to find its velocity.

So substituting the given values in the above formula to find the velocity of the truck.

Truck's velocity = $\frac{40120}{1180}$ = 34 m/s.

3 0

3 years ago