Question

a car takes off from rest and covers a distance of 80m on a straight road in 10s.calculate the magnitude of its acceleration

Answer 1

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Here's the solution :

Let's find the final velocity :

• $\dfrac{displacement}{time}$

• $\dfrac{80}{10}$

• $8 \: \: ms {}^{ - 1}$

Initial velocity (u) = 0 (cuz it started from rest)

Final velocity (v) = 8 m/s

Time taken (t) = 10 sec

now, we know that :

• $acceleration = \dfrac{v - u}{t}$

• $\dfrac{8 - 0}{10}$

• $\dfrac{8}{10}$

• $0.8 \: \: m {s}^{ - 2}$

Acceleration = 0.8 m/s²