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Yuri [45]
3 years ago
10

A force acting over a large area will exert less pressure per square inch than the same force acting over a smaller area.

Physics
1 answer:
babunello [35]3 years ago
8 0

Answer:

True

Explanation:

Pressure is defined as:

p=\frac{F}{A}

where

F is the magnitude of the force perpendicular to the surface

A is the surface

Therefore, pressure is inversely proportional to the area of the surface:

p\propto \frac{1}{A}

this means that, assuming that the forces in the two situations (which have same magnitude) are both applied perpendicular to the surface, the force exerted over the smaller area will exert a greater pressure. Hence, the statement"

<em>"A force acting over a large area will exert less pressure per square inch than the same force acting over a smaller area"</em>

is true.

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One student did an experiment with two unknown minerals, Mineral 1 and Mineral 2. The hardness scale shown below was used for th
Umnica [9.8K]
Scale: (soft 1-->6 hardest)
<span>1=Talc 2=Gypsum 3=Calcite 4=Fluorite 5=Apatite 6=Orthoclase

</span>Mineral #1 can only scratch two other minerals therefore it must have a hardness level of 2+1=3 which is Calcite. (scratches talc, gypsum)

Mineral #2 can scratch four other minerals therefore it must have a hardness level of 4+1=5 which is Apatite. (scratches all but Apatite, Orthoclase)

Looking through the possible conclusions.. It looks like answer is D.


3 0
3 years ago
A helicopter is ascending vertically. a passenger accidentally drops her wallet out the sides of the helicopter when it is 160 m
Advocard [28]

Answer:

(E)56.0 m/s

Explanation:

Height =h=-160 m

Because the wallet moving in downward direction

Time=t=7 s

Final speed of wallet=v=0

We have to find the speed of helicopter ascending  at the moment when the passenger let go of the wallet.

v^2-u^2=2gh

Where g=9.8 m/s^2

Substitute the values

0-u^2=2(-160)\times 9.8

u^2=3136

u=\sqrt{3136}=56m/s

Option (E) is true

8 0
4 years ago
How did tycho brahe's model of the universe differ from the greek geocentric model?
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4 0
3 years ago
Two blocks, joined by a string, have masses of 6.0 and 9.0 kg. They rest on a frictionless, horizontal surface. A second string,
Lynna [10]

Answer:

T= 27 N

Explanation:

Assuming that the string joining both masses is massless  and inextensible, both masses accelerate at the same rate.

So, we can treat to both masses as a single system, and apply Newton's 2nd Law to both masses.

In this way, we can get the value of the acceleration without taking into account the tension in the string, as it is an internal force (actually a action-reaction pair).

Newton's 2nd law is a vector equation, so we can decompose the forces along perpendicular axis in order to convert it in two algebraic equations.

We can choose one axis as parallel to the horizontal surface (we call it x-axis, being the positive direction the one of  the movement of the blocks due to the horizontal force applied to the 6.0 kg block), and the other, perpendicular to it, so it is vertical (we call y-axis, being the upward direction the positive one).

Taking into account the forces acting  on both masses, we can write both equations as follows:

Fy = N- (m₁+m₂)*g = 0 (as there is no movement in the vertical direction)

Fx = Fh = (m₁ + m₂) * a ⇒ 45 N = 15.0 kg * a

⇒ a = 45 N / 15.0 kg = 3 m/s²

Now, in order to get the value of the tension T, we can choose as our system, to any mass, and apply Newton's 2nd Law again.

If we choose to the mass of 6.0 kg, in the horizontal direction, there are two forces acting on it, in opposite directions: the  horizontal applied force of 45 N, and the tension in the string that join both masses.

The difference of both forces, must be equal to the mass (of this block only) times the acceleration, as follows:

F- T = m₂* a ⇒ 45 N - T = 6.0 kg * 3 m/s²

⇒ T = 45 N -18 N = 27 N

We could have arrived to the same result taking the 9.0 Kg as our system, as the only force acting in the horizontal direction is just the tension in the string that we are trying to find out, as follows:

F = m₁*a = 9.0 kg* 3 m/s² = 27 N

4 0
3 years ago
If we increase the force applied to an object and all other factors remain the same that amount of work will
worty [1.4K]
Hello there.

<span>If we increase the force applied to an object and all other factors remain the same that amount of work will

</span><span>C. Increase
</span>
5 0
3 years ago
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