<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>
We can write this as the difference of squares:
(5b⁸+8c)(5b⁸-8c)
To write as the difference of squares, take the square root of each term first:
√25b¹⁶ = 5b⁸; √64c² = 8c
Now we write this as a sum in one binomial and a difference in the other:
(5b⁸+8c)(5b⁸-8c)
Answer:
I believe the question says "5j + 16 - 12(-9j - 4) - 12j" I hope I'm correct because I have almost no idea what you typed.
If you did type "5j + 16 - 12(-9j - 4) - 12j" then your answer would be 133j + 52 I believe. You never put how you would like your problem to be solved, so I simplified.
Step-by-step explanation:
Hope this helps.
Answer:
First option 
is the correct answer.
Step-by-step explanation:
Let us consider each part, we have number 6 inside all the roots.
First we have to find cube root of 6.
![\sqrt[3]{6} =6^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B6%7D%20%3D6%5E%5Cfrac%7B1%7D%7B3%7D)
Now we have to find square root of this value.
So, first option is the correct answer.
