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ra1l [238]
3 years ago
10

Write the equation of the line in fully simplified slope-intercept form.

Mathematics
1 answer:
lyudmila [28]3 years ago
7 0

Step-by-step explanation:

Kdlsödd d eşi m s ol ma Du m bakalım bu kim lan diye

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Please answer the problem and show your work.Thank you.
Vinvika [58]

Answer:

8. m=6

9.  x=2; Alyssa is incorrect because she subtracted 8 from 16 when in reality she should have divided 16 by 8 to get 2. The real solution is 2 because 8 times 2 is equal to 16.

Step-by-step explanation:

Question 8:

2m-6=m

-2m    -2m     (subtract 2m from both sides)

<u>-6</u>=<u>-m</u>  

-       -     (divide both sides by the negative)

m=6

Question 9:

<u>8x</u>=<u>16  </u>              (divide both sides of the equation by 8)

8     8

x=2

8 0
1 year ago
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A number equivalent to 63.24
tankabanditka [31]
63.24 is equivalent to 63.240.
7 0
4 years ago
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Radius of x^2+y^2=25
SOVA2 [1]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
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Use the pythagorean Theorem to find the value of m<br> A) 16 <br> B) 12<br> C) 20<br> D) 256
Leto [7]

Answer:

A is the correct answer

8 0
3 years ago
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Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
3 years ago
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