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True [87]
3 years ago
7

What question do you ask when checking your answer and presenting the solution?

Mathematics
1 answer:
frozen [14]3 years ago
8 0
What is the hypothesis?
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I need help on this one question ;(
Law Incorporation [45]

Answer:

C

Step-by-step explanation:

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4 years ago
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90 Points plz help!!!
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Y=7x-1 is that what youre looking for?
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3 years ago
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Nicki Plans to attend a state university in two years. Thanks to girls from relatives and earnings from an afterschool job, she
Crazy boy [7]

Answer:

Step-by-step explanation:

Thanks to girls from relatives and earnings from an afterschool job, she has already saved $3700. If she's a seed in her goal of saving $150 per month, then if she saves for x months, the total amount that she would be have earned is

150x + 3700

1 year = 24 months

If she saves for 2 years, it means that the number of months for which she saved is 2 × 12 = 24 months. Therefore, the total amount

that she will have two years from now is

150 × 24 + 3700

= 3600 + 3700

= $7300

7 0
3 years ago
Which of the following is a rational function
VARVARA [1.3K]
I believe the answer is c
7 0
4 years ago
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Calc help pretty please
Gre4nikov [31]

Answer:

A.  77.4

Step-by-step explanation:

<u>Linear approximation formula</u>

L(x)=f(a)+f'(a)(x-a)

Given function:

f(x)=(x+1)^2

\boxed{\begin{minipage}{5.4 cm}\underline{Chain Rule for Differentiation}\\\\If  $y=f(u)$  and  $u=g(x)$  then:\\\\$\dfrac{\text{d}y}{\text{d}x}=\dfrac{\text{d}y}{\text{d}u}\times \dfrac{\text{d}u}{\text{d}x}$\\\end{minipage}}

\boxed{\begin{minipage}{5 cm}\underline{Differentiating $x^n$}\\\\If  $y=x^n$, then $\dfrac{\text{d}y}{\text{d}x}=xn^{n-1}$\\\end{minipage}}

\boxed{\begin{minipage}{4 cm}\underline{Differentiating $ax$}\\\\If  $y=ax$, then $\dfrac{\text{d}y}{\text{d}x}=a$\\\end{minipage}}

Use the chain rule to differentiate the function.

\textsf{Let }\:y=u^2\:\textsf{ where }u=(x+1)

Differentiate the two parts separately:

  y=u^2 \implies \dfrac{\text{d}y}{\text{d}u}=2u

  u=x+1 \implies \dfrac{\text{d}u}{\text{d}x}=1

Put everything back into the chain rule formula:

\begin{aligned} \implies \dfrac{\text{d}y}{\text{d}x} & =2u \times 1\\ & = 2u \\ & = 2(x+1)\\ & = 2x+2 \end{aligned}

\textsf{Therefore, }\:f'(x)=2x+2..

The <u>linear approximation</u> at a = 8 is:

\begin{aligned}L(x) & =f(a)+f'(a)(x-a)\\\\\implies L(x) & = f(8)+f'(8)(x-8)\\& = (8+1)^2+(2(8)+2)(x-8)\\& = 81+18(x-8)\\& = 18x-63\end{aligned}

Finally, substitute x = 7.8 into the <u>linear approximation equation</u>:

\begin{aligned}\implies L(7.8) & =18(7.8)-63\\& = 140.4-63\\& = 77.4\end{aligned}

4 0
2 years ago
Read 2 more answers
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