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3 years ago

What question do you ask when checking your answer and presenting the solution?

Mathematics

1 answer:

frozen [14]3 years ago

8 0

What is the hypothesis?

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Which function represents exponential decay? f(x) = One-half (three-halves) Superscript x f(x) = One-half (negative three-halves

viva [34]

Answer:

$f(x) = 4(\frac{2}{3})^{x}$

Step-by-step explanation:

The first function is given as, $f(x) = \frac{1}{2}(\frac{3}{2})^{x}$ .

Now, the value of this function increases i.e. value of f(x) increases as the x-value increases because $\frac{3}{2} > 1$ .

Now, the second function is given as, $f(x) = \frac{1}{2}(- \frac{3}{2} )^{x}$ .

This function can not be considered as a continuous function because $- \frac{3}{2} < 0$ .

Again, the third function is given as, $f(x) = 4(- \frac{2}{3})^{x}$ .

This function can also not be considered as a continuous function because $- \frac{2}{3} < 0$ .

Finally, the fourth function is given to be, $f(x) = 4(\frac{2}{3})^{x}$ .

In this function, the value of f(x) continuously decreases as the value of x increases, because $0 < \frac{2}{3} < 1$ .

Therefore, this function represents exponential decay. (Answer)

10 0

3 years ago

Read 2 more answers

What is the slope of the line that contains the point (-1,2) and (3,3)

stepan [7]

The slope of that line would be 1/4!!!

4 0

3 years ago

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Solve the system algebraically. Check your work.

Alika [10]

Hey there! :D

We can subtract the equations from each other.

4x-3x=x

2y-2y=0

10-6=4

x=4 <== that's all we have left of the equation

Now plug that in to solve.

3(4)+2y=6

12+2y=6

2y=-6

y=-3

Solution: (4,-3)

I hope this helps!
~kaikers

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3 years ago

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Is 2.8 greater than or less than 2.78? Pls answer

KengaRu [80]

2.8 is greater than 2.78 :)

If you look in the tens place and compare the two numbers, you will see that 8 is greater than 7. That’s how you know that 2.8 is greater than 2.78

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3 years ago

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Explain how Main Sequence Stars

iogann1982 [59]

A giant star is a star with substantially larger radius and luminosity than a main-sequence (or dwarf) star of the same surface temperature. They lie above the main sequence (luminosity class V in the Yerkes spectral classification) on the Hertzsprung–Russell diagram and correspond to luminosity classes II and III.

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