Answer:
Δ BEC ≅ Δ AED
Step-by-step explanation:
Consider triangles BCA and ADB. Each of them share a common side, AB. Respectively each we should be able to tell that AD is congruent to BC, and DB is congruent to CA, so by SSS the triangles should be congruent.
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So another possibility is triangles BEC, and AED. As you can see, by the Vertical Angles Theorem m∠BEC = m∠ADE, resulting in the congruency of an angle, rather a side. As mentioned before AD is congruent to BC, and perhaps another side is congruent to another in the same triangle. It should be then, by SSA that the triangles are congruent - but that is not an option. SSA does is one of the exceptions, a rule that is not permitted to make the triangles congruent. Therefore, it is highly unlikely that triangles BEC and AED are congruent, but that is what our solution, comparative to the rest.
Δ BEC ≅ Δ AED .... this is our solution
15% of R560 - 15% of R500
=> 0.15 × 560 – 0.15 × 500
=> 0.15 ( 560–500)
=> 0.15 × 60
=> Rs. 9
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The area of the triangle is 36 in², so she can create only 4 triangles.
Answer:
See Below
Step-by-step explanation:
Thankfully, all the parts you need are given.
First, find the surface of one triangle
A = 1/2bh
A = 1/2(15)(9)
A = 1/2(135)
A = 67.5
Multiply by 4 to get the sum of all the sides.
67.5(4) = 270
Now find the surface area of one square
A = bh
A = (15)(15)
A = 225
multiply by 5 to get all 5 sides
225(5) = 1125
Add sums together
1125 + 270 = 1395
I think the greatest number less than 700 with 9 in the tens place and different digits in each of the other places is 698.
I chose 6 to be in the one of hundreds place because it is the greatest number that is less than 7 in the hundreds place. I also chose 8 to be in the ones place because it is different from 6 and 9 and the greatest number in the ones place that is not 9.
