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Ilya [14]
3 years ago
8

Quadrilateral LMNO has diagonals that intersect at point P. If LP=NP, MP = y + 25, and OP = 5y + 29, find the length of MO such

that LMNO is a parallelogram.. . A.24. B.48. C.61. D.122
Mathematics
2 answers:
salantis [7]3 years ago
8 0
The right  answer will be  c.61 that is your answer
Zina [86]3 years ago
8 0

Answer:

The correct option is B.

Step-by-step explanation:

Given information: LMNO is a parallelogram, LMNO has diagonals that intersect at point P, LP=NP, MP = y + 25, and OP = 5y + 29.

Diagonals of parallelogram bisects each other.

Since P is the intersection point of diagonal and MO is a diagonal, so

MP=OP

y+25=5y+29

Subtract y from both the sides.

y+25-y=5y+29-y

25=4y+29

Subtract 29 from both the sides.

25-29=4y+29-29

-4=4y

Divide both sides by 4.

-1=y

The value of y is -1.

The length of MO is

MO=MP+OP

MO=y+25+5y+29

MO=6y+54

Substitute y=-1 in the above equation.

MO=6(-1)+54

MO=-6+54

MO=48

The length of MO is 48. Therefore the correct option is B.

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Starter
4vir4ik [10]

Answer:

1) £2 = €2.32

£5 = €5.80

£50 = €58

2) The graph will be a straight line

3) (0, 0)

4) Label the independent variable, £ on the x-axis and dependent variable € on the y-axis

Step-by-step explanation:

1) The given conversion factors is £1 = €1.16

Therefore;

£2 = 2 × €1.16 = €2.32

£2 = €2.32

£5 = 5 × €1.16 = €5.80

£5 = €5.80

£50 = 50 × €1.16 = €58

£50 = €58

2) The shape of the plot of the directly proportional currencies graph will be a straight line

3) Given that the £ is directly proportional to the € and that the value of the € can be found directly by multiplying the amount in £ by 1.16, without the addition of a constant, the graph crosses the axes at the origin (0, 0)

4) The y-axes which is the dependent variable should be labelled €, while the x-axis which is the independent variable should be labelled £

4 0
2 years ago
Parking lot has 121 spots. Ratio of senior to junior is 7 to 4. How many spots go to each grade level?
Andrej [43]
I am going to build a chart this is best when using ratios 

              seniors    junior  total
                 7              4       
                 *?             *?     *?
    Totals                          121   

The way we fill out this chart is that we add the rows and multiply the columns. 

So we add 7 + 4 and fill it in our chart we get 11 

            seniors    junior  total
                 7              4       11
                 *?             *?     *?
    Totals                          121   

now to find the *? need to divide 121/11 to get *?

121/11 = 11

so now our chart looks like this 
            seniors    junior  total
                 7              4       11
                 11            11     11
    Totals                          121   

Now we multiply each column 

so
7 * 11  = 77
 4*11 = 44

now our chart look like this 

            seniors    junior  total
                 7              4       11
                 11            11     11
    Totals     77           44      121   

so seniors get 77 spaces 
and juniors get 44 spaces. 

6 0
3 years ago
Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete
icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 17 means that N = 17

4 are carrying nucleas weapons, which means that k = 4

9 are destroyed, which means that n = 9

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X > 1) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294

P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0
3 years ago
Picture Added Triangles <br> AA <br> SSS<br> SAS<br> Not Similar
rewona [7]

Answer:

Not Similer

Step-by-step explanation:

we can use the process of elimination, first AA isn't it because the corresponding angles arn't equal, next SSS itsn't it because we don't know the side lengths, and lastly SAS isn't it because we still don't know the side lengths.

5 0
3 years ago
The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the
ohaa [14]

Answer:

A.48

Step-by-step 789333

6 0
3 years ago
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