So we have v(w) = 2w - 1
Now we make the following change: w ---> w +3.
So we change every "w" into a "w+3" as follows:
v(w) = 2w - 1 --------> v(w+3) = 2*(w+3) - 1
Let's solve this.
2*(w+3) - 1
2*w + 2*3 - 1
2w + 6 - 1
2w + 5
So
v(w+3) = 2w + 5
First find the gradient of line AB
14--3/7--10
17/17 = 1
As CD is perpendicular to AB take the negative reciprocal of the gradient to AB to find gradient of CD
Gradient of CD = -1
to find y intercept use points given
12=(-1 x 5) +c
17 = c
C is the y intercept so for question 1 the answer is 3
for the second question just plug values into the equation and see if you get the right y value
Here the only number that works is -2
for question 2
the answer is 2
Answer:
b. -2/3
Step-by-step explanation:
in addition a negative plus a negative does not equal a positive so we can already assume the answer is b but to be safe we can work this problem out in this way: 1/9 + 5/9 = 6/9 we simplify 6/9 and we get 2/3 so we slap the negative back on and boom -2/3
As time goes on the speed is changing
Ok ok ok ok ok ok ok ok ok
