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3 years ago

Ik ik this is the last one lolbut I really need this

Mathematics

2 answers:

FinnZ [79.3K]3 years ago

8 0

I would say the second one - 2/3

yawa3891 [41]3 years ago

6 0

Answer:

b. -2/3

Step-by-step explanation:

in addition a negative plus a negative does not equal a positive so we can already assume the answer is b but to be safe we can work this problem out in this way: 1/9 + 5/9 = 6/9 we simplify 6/9 and we get 2/3 so we slap the negative back on and boom -2/3

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If 9 less than 6 times a number lies between 31 and 37, what is the number

rjkz [21]

Answer:

Step-by-step explanation:

6x6=36

7x6=42

8x6=48

36-9=25 thus it isn't possible because it's not between 31 and 37. 48-9=39 hence also not possible. However for 42, it is defintely possible. Thus answer is 7

8 0

4 years ago

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Find the percent of decrease from 310 to 140. Round to the nearest tenth of a percent if necessary.

JulijaS [17]

54.8% I think I'm not sure

4 0

3 years ago

How can you write 31/6 as a mixed number

shutvik [7]

$31/6 = 5 \frac{1}{6}.$

Count how many times 6 goes into 31 that is 5. Remainder 1. Which means $5 \frac{1}{6}$

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3 years ago

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Write the rule for the pattern 100,81,64,49,36

sergiy2304 [10]

I’m not sure what the rule would be in this context, but those are just the squares of decreasing numbers starting at 10. It’s 10^2, then 9^2, then 8^2, and so on.

4 0

3 years ago

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In a random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand. C

horrorfan [7]

Answer:

90% confidence interval for the proportion of fans who bought food from the concession stand

(0.5603,0.6529)

Step-by-step explanation:

Step(i):-

Given sample size 'n' =300

Given data random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand.

Given sample proportion

$p^{-} = \frac{x}{n} = \frac{182}{300} =0.606$

level of significance = 90% or 0.10

Z₀.₁₀ = 1.645

90% confidence interval for the proportion is determined by

$(p^{-} - Z_{0.10}\sqrt{\frac{p(1-p)}{n} } , p^{-} +Z_{0.10}\sqrt{\frac{p(1-p)}{n} })$

$(0.6066 - 1.645\sqrt{\frac{0.6066(1-0.6066)}{300} } ,0.6066+1.645\sqrt{\frac{0.6066(1-0.6066)}{300} })$

(0.6066 - 0.0463 ,0.6066 + 0.0463)

(0.5603,0.6529)

final answer:-

90% confidence interval for the proportion of fans who bought food from the concession stand

(0.5603,0.6529)

5 0

3 years ago

Ik ik this is the last one lolbut I really need this ​

Ik ik this is the last one lolbut I really need this