Question

PLEASE

Answer 1

Answer:

First blank (17,0)

Option 3 is correct

Second Blank (-2,19)

Option 2 is correct  

Step-by-step explanation:

CD is perpendicular to AB

C(5,12)

A(-10,-3)

B(7,14)

CD ⊥ AB

Thus, Slope of CD is negative inverse of slope of AB

$\text{Slope of AB }=\dfrac{14+3}{7+10}$

                          $m=1$

Slope of CD, m=-1  (CD ⊥ AB )

Point C: (5,12)

Equation of line CD,

$y-12=-1(x-5)$

$y=-x+17$

For x-intercept: Put y=0

$0=-x+17$

$x=17$

x-intercept: (17,0)

For second blank we have to check each point.

Option 1: (-5,24) ,Put x=-5 and y=24

$24=5+17$

$24\neq 22$

False

Option 2: (-2,19) ,Put x=-2 and y=19

$19=2+17$

$19=19$

True

Option 3: (7,-10) ,Put x=7 and y=-10

$-10=-7+17$

$-10\neq 10$

False

Option 4: (8,11) ,Put x=8 and y=11

$11=-8+17$

$11\neq 9$

False

Hence, First blank (17,0) and Second blank (-2,19)

Answer 2

First find the gradient of line AB

14--3/7--10

17/17 = 1

As CD is perpendicular to AB take the negative reciprocal of the gradient to AB to find gradient of CD

Gradient of CD = -1

to find y intercept use points given

12=(-1 x 5) +c

17 = c

C is the y intercept so for question 1 the answer is 3

for the second question just plug values into the equation and see if you get the right y value

Here the only number that works is -2

for question 2

the answer is 2